Answer:
801 g
Explanation:
From the question given above, the following data were obtained:
Number of mole of Ba₃(PO₄)₂ = 1.33 moles
Mass of Ba₃(PO₄)₂ =?
Next, we shall determine the molar mass of Ba₃(PO₄)₂. This can be obtained as follow:
Molar mass of Ba₃(PO₄)₂ = (137.3×3) + 2[31 + (4×16)]
= 411.9 + 2[31 + 64]
= 411.9 + 2[95]
= 411.9 + 190
Molar mass of Ba₃(PO₄)₂ = 601.9 g/mol
Finally, we shall determine the mass of Ba₃(PO₄)₂. This can be obtained as follow:
Number of mole of Ba₃(PO₄)₂ = 1.33 moles
Molar mass of Ba₃(PO₄)₂ = 601.9 g/mol
Mass of Ba₃(PO₄)₂ =?
Mole = mass /Molar mass
1.33 = Mass of Ba₃(PO₄)₂ / 601.9
Cross multiply
Mass of Ba₃(PO₄)₂ = 1.33 × 601.9
Mass of Ba₃(PO₄)₂ = 801 g
Answer:
The new volume of this gas is 6.86 liters.
Assumption: the temperature of this gas stays the same, and this gas is ideal such that Boyle's Law applies.
Explanation:
By Boyle's Law, the volume of an ideal gas shall be inversely proportional to the pressure on it when temperature stays the same (as in an isothermal process.)
In other words,
,
where
is the volume of the gas, and
is the pressure on the gas.
.
.
Assume that this gas is ideal. Also assume that this increase in pressure is isothermal. Apply Boyle's Law to find the new volume of this gas:
.
Nuclear reactions<span> involve a change in the atom's nucleus, they usually produce a different element & c</span>hemical reactions<span> only involve a rearrangement of electrons and do not involve changes in the nuclei.</span>
As overall compound is neutral so , let oxidation number of P be x
4(x) + (-2)8 = 0
x = +4
Number of moles of the gas, Temperature and the volume of the gas.
