Donny drove 70 miles.
Since 60 miles per hour is 1 mile a minute so for in 45 minutes he drove 45 miles. After he drove for 50 miles for thirty minutes so in totally he drove 25 since 50 divided by two is 25.
X2 - 8x + 15 = 0
(x - 3)(x - 5) = 0
critical points are at 3 and 5
<h2>
Hello!</h2>
The answer is:
The correct option is:
D. 40 feet.
<h2>
Why?</h2>
To solve the problem and calculate the width of the river, we need to assume that the distance from A to B and the angle formed between that distance and the distance from A to the other point (C) is equal to 90°, meaning that we are working with a right triangle, also, we need to use the given angle which is equal to 34°. So, to solve the problem we can use the following trigonometric relation:

Where,
alpha is the given angle, 34°
Adjacent is the distance from A to B, which is equal to 60 feet.
Opposite is the distance from A to C which is also equal to the width of the river.
So, substituting and calculating we have:


Hence, we have that the correct option is:
D. 40 feet.
Have a nice day!
Check the picture below.
since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.
1)
![\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cone%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D3%5C%5C%20h%3D4%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B%5Cpi%20%283%29%5E2%284%29%7D%7B3%7D%5Cimplies%20V%3D12%5Cpi%20%5Cimplies%20V%5Capprox%2037.7)
2)
now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.
![\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20sphere%7D%5C%5C%5C%5C%20V%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D3%20%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Ccfrac%7B4%5Cpi%20%283%29%5E3%7D%7B3%7D%5Cimplies%20V%3D36%5Cpi%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bhalf%20of%20that%20for%20a%20semisphere%7D%7D%7BV%3D18%5Cpi%20%7D%5Cimplies%20V%5Capprox%2056.55)
3)
well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.
4)
pretty much the same thing, we get the volume of the cone and its top, add them up.

The author uses paragraph 12 to create tension because of <u>D.The author</u> increases a feeling of discomfort with descriptions of conflict and disagreement.
<h3>What is tension in storytelling?</h3>
Tension is a storytelling technique to ensure that readers do not drop a novel but keep readers engaged.
Creating tension helps the readers of a story to emotionally invest in the story, the characters, and the scenes.
Some authors use the following strategies to create tension?
- Raising the stakes.
- Creating crucial conflicts.
- Making the reader ask questions.
- Allowing tension to ebb and flow.
- Creating secondary sources of tension.
- Creating internal and external conflicts.
- Unfolding the story in a shorter space of time.
- Create engaging characters with opposing goals.
Thus, the author increases a feeling of discomfort with descriptions of conflict and disagreement.
Learn more about tensions in storytelling at brainly.com/question/1928029
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