Answer:
the answer is h=0.5m+2 I think
4.5 boxes of nails are required for finishing 2 tables
Step-by-step explanation:
Given:
3.4 boxes of nails are required for finishing 1.5 tables
Required:
How much boxes of nails would he use for finishing 2 tables
Solution:
We can solve using Unitary Method:
Nails needed to finish 1.5 tables = 3.4 boxes
Nails needed to finish 1 table = 
Nails needed to finish 2 tables = 
So, 4.5 boxes of nails are required for finishing 2 tables.
Keywords: Word Problems
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In the above problem, you want to find the number of multiples of 7 between 30 and 300.
This is an Arithmetic progression where you have n number of terms between 30 and 300 that are multiples of 7. So it is evident that the common difference here is 7.
Arithmetic progression is a sequence of numbers where each new number in the sequence is generated by adding a constant value (in the above case, it is 7) to the preceding number, called the common difference (d)
In the above case, the first number after 30 that is a multiple of 7 is 35
So first number (a) = 35
The last number in the sequence less than 300 that is a multiple of 7 is 294
So, last number (l) = 294
Common difference (d) = 7
The formula to find the number of terms in the sequence (n) is,
n = ((l - a) ÷ d) + 1 = ((294 - 35) ÷ 7) + 1 = (259 ÷ 7) + 1 = 37 + 1 = 38
Answer:
2 5/8
Step-by-step explanation:
simple met... I mean math :)
Answer:
A. cos(t)= 1/sec(t)
Second answer is C. 12/13
Step-by-step explanation:
Just had the question.