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2 years ago

QUESTION 7

Mathematics

1 answer:

elena-s [515]2 years ago

4 0

The average winning per bet is the mean or the expected value of winning a bet.

The statistical term that represents $0.94 is (c) the expected value

From the question, we understand that the gambler has an average winning of $0.94, when he places a bet of $1

This means that:

The average winning on a bet of $1 is $0.94

Average, in statistics means the mean or expected value

Hence, the statistical term for $0.94 is (c) the expected value

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the equation a = represents the angle measures, a, in a regular n-sided polygon. when the equation is solved for n, n is equal t

mario62 [17]

A = 180(n - 2)

a = 180n - 180*2

a = 180n - 360

180n - 360 = a

180n = a + 360

n = (a + 360) / 180

Numerator for fraction above = ( a + 360), denominator = 180

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2 years ago

Read 2 more answers

Help I can't fail! pleaseeeee

VLD [36.1K]

Answer:

Step-by-step explanation:

I believe it's C.33 because if 4×33=132 the rest are smaller and one of the is equal,

So in my opinion It's 33

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3 years ago

Solve 31-X + (2 x + 1)] = x - 1.

Kobotan [32]

Answer:

x = X + 33 (I am guessing "x" and "X" are not the same. "x" is a variable and "X" is a constant.)

Step-by-step explanation:

31 - X + (2x+1) = x - 1

or, 2x+1 = x - 1 - 31 + X

or, 2x - x = -1 -31 + X -1

or, x = -2 -31 + X

or, x = X - 33

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2 years ago

If angle 1 and angle 2 form linear pair and m angle 1 =50, then m angle = 2

Irina-Kira [14]

Measure of angle 2 would be 130 degrees because since it forms a linear pair the two angles added together have to equal 180 degrees so
180 - 50 = 130

8 0

3 years ago

Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule

Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

a) What is the approximate percentage of men between 169 and 183 cm?

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

$\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183$

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

b) Between which 2 heights would 95% of men fall?

This corresponds to ±2 standard deviations off the mean.

$\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190$

95% of the men will fall between 162 cm and 190 cm.

c) Is it unusual for a man to be more than 197 cm tall?

The number of standard deviations of distance from the mean is

$n=(197-176)/7=3$

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

3 0

3 years ago