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Sindrei [870]
2 years ago
6

The mass of one Be atom is

Chemistry
1 answer:
Vilka [71]2 years ago
5 0

The atomic mass unit, or amu, is 1/12 the mass of one atom of carbon-12. An atomic mass unit has the mass of 1/(6.0221415 * 10^23) grams.

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If an ice cube weighing 25.0 g with an initial
riadik2000 [5.3K]

Answer:

11

∘

C

Explanation:

As far as solving this problem goes, it is very important that you do not forget to account for the phase change underwent by the solid water at

0

∘

C

to liquid at

0

∘

C

.

The heat needed to melt the solid at its melting point will come from the warmer water sample. This means that you have

q

1

+

q

2

=

−

q

3

(

1

)

, where

q

1

- the heat absorbed by the solid at

0

∘

C

q

2

- the heat absorbed by the liquid at

0

∘

C

q

3

- the heat lost by the warmer water sample

The two equations that you will use are

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of water, equal to

4.18

J

g

∘

C

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

and

q

=

n

⋅

Δ

H

fus

, where

q

- heat absorbed

n

- the number of moles of water

Δ

H

fus

- the molar heat of fusion of water, equal to

6.01 kJ/mol

Use water's molar mass to find how many moles of water you have in the

100.0-g

sample

100.0

g

⋅

1 mole H

2

O

18.015

g

=

5.551 moles H

2

O

So, how much heat is needed to allow the sample to go from solid at

0

∘

C

to liquid at

0

∘

C

?

q

1

=

5.551

moles

⋅

6.01

kJ

mole

=

33.36 kJ

This means that equation

(

1

)

becomes

33.36 kJ

+

q

2

=

−

q

3

The minus sign for

q

3

is used because heat lost carries a negative sign.

So, if

T

f

is the final temperature of the water, you can say that

33.36 kJ

+

m

sample

⋅

c

⋅

Δ

T

sample

=

−

m

water

⋅

c

⋅

Δ

T

water

More specifically, you have

33.36 kJ

+

100.0

g

⋅

4.18

J

g

∘

C

⋅

(

T

f

−

0

)

∘

C

=

−

650

g

⋅

4.18

J

g

∘

C

⋅

(

T

f

−

25

)

∘

C

33.36 kJ

+

418 J

⋅

(

T

f

−

0

)

=

−

2717 J

⋅

(

T

f

−

25

)

Convert the joules to kilojoules to get

33.36

kJ

+

0.418

kJ

⋅

T

f

=

−

2.717

kJ

⋅

(

T

f

−

25

)

This is equivalent to

0.418

⋅

T

f

+

2.717

⋅

T

f

=

67.925

−

33.36

T

f

=

34.565

0.418

+

2.717

=

11.026

∘

C

Rounded to two sig figs, the number of sig figs you have for the mass of warmer water, the answer will be

T

f

=

11

∘

C

Explanation:

3 0
2 years ago
Cell Membranes
Lerok [7]

The procedure to perform a cell membrane experiment is to:

  • Use beetroots cells to measure the permeability of the membrane
  • This is done to check the content of the pigment
  • It is also meant to check the pigment leaks out of the cells.

<h3>What is a Cell Membrane?</h3>

This refers to the semi-permeable membrane that is around the cytoplasm of a cell.

Hence, we can see that the main purpose of the cell membrane practical experiment is to test the permeability of a membrane and to see the amount of liquid that a membrane can hold.

Please note that your question is incomplete so I gave you a general overview to get a better understanding of the concept.

Read more about cell membrane here:

brainly.com/question/1768729

#SPJ1

4 0
2 years ago
All of the following are examples of matter except
Alexxandr [17]

A. Heat because it does not take up space.

3 0
3 years ago
Help this question is super hard!!
melomori [17]

Answer:

They all can, but  HCl would be the strongest conductors because they are strong acids/bases, meaning their ions dissociate at a faster rate in aqueous solution.

4 0
3 years ago
Read 2 more answers
How are organelles specialized to perform various tasks in a cell?
aksik [14]

Answer:

Organelles are structures within a cell that perform specific functions like controlling cell growth and producing energy. Plant and animal cells can contain similar types of organelles. However, certain organelles can only be found in plant cells and certain organelles can only be found in animal cells.

8 0
2 years ago
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