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3 years ago

How many moles are in 563.9 grams of arsenic?

Chemistry

1 answer:

Aleks [24]3 years ago

6 0

Answer:

No. of moles, n = 7.52 moles

Explanation:

Given that,

Mass, m = 563.9 grams

Molar mass of arsenic = 74.92 g/mol

We need to find the number of moles in 563.9 grams of arsenic. Let it is denoted by n. It is equal to given mass divided by total molar mass.

$n=\dfrac{563.9 }{74.92}\\\\=7.52\ \text{moles}$

So, there are 7.52 moles in 563.9 grams of arsenic.

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Arrange the following elements in order of increasing (from smallest to largest) atomic size: H, Br, Cl, O. Explain the reasonin

juin [17]

Explanation:

Atomic size is defined as the distance between the nucleus and valence shell of an atom. Valence shell is the outermost shell of an atom.

When we move across a period in a periodic table then there will occur a decrease in atomic size of the atoms. But when we move across a group in a periodic table then there will occur an increase in atomic size of the atom.

Hydrogen is a period 1 element, oxygen is a period 2 element, chlorine is a period 3 element and bromine is a period 4 element.

Therefore, given elements are arranged in order of increasing atomic size as follows.

H < O < Cl < Br

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3 years ago

In an experiment magnesium ribbon was heated in air. The product was found to be heavier than the original ribbon. Potassium man

KatRina [158]

Burning a magnesium ribbon in the air is an addition reaction while heating potassium manganate 7 is a decomposition reaction.

<h3>Addition and decomposition reactions</h3>

Magnesium burns in air to produce magnesium oxide as follows:

$2Mg + O_2 --- > 2MgO$

Potassium manganate 7 burns to produce multiple products as follows:

$2 KMnO_4 --- > K_2MnO_4 + MnO_2(s) + O_2$

Thus, the MgO will be heavier than Mg. On the other hand, $MnO_2$ will be less heavy than $KMnO_4$ .

More on reactions can be found here: brainly.com/question/17434463

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7 0

2 years ago

The value of Kp for the reaction NO(g) 1 1 2 O2(g) 4 NO2(g) is 1.5 3 106 at 25°C. At equilibrium, what is the ratio of PNO2 to P

expeople1 [14]

Answer : The ratio of $p_{NO_2}$ to $p_{NO}$ is, $6.87\times 10^5$

Solution : Given,

$K_p=1.5\times 10^6$

$p_{O_2}$ = 0.21 atm

The given equilibrium reaction is,

$NO(g)+\frac{1}{2}O_2\rightleftharpoons NO_2(g)$

The expression of $K_p$ will be,

$K_p=\frac{(p_{NO_2})}{(p_{NO})\times (p_{O_2})^{\frac{1}{2}}}$

Now put all the given values in this expression, we get:

$1.5\times 10^6=\frac{(p_{NO_2})}{(p_{NO})\times (0.21)^{\frac{1}{2}}}$

$\frac{(p_{NO_2})}{(p_{NO})}=(1.5\times 10^6)\times (0.21)^{\frac{1}{2}}$

$\frac{(p_{NO_2})}{(p_{NO})}=6.87\times 10^5$

Therefore, the ratio of $p_{NO_2}$ to $p_{NO}$ is, $6.87\times 10^5$

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3 years ago

When heat energy is removed, two changes are observed:

harkovskaia [24]

Answer: Option (A) is the correct answer.

Explanation:

Condensation is defined as the process in which vapors or gaseous phase changes into liquid phase.

Freezing is the process in which liquid phase changes into solid phase.

Evaporation is the process in which liquid phase changes into vapors or gaseous phase.

Melting is the process in which solid phase changes into liquid phase.

Therefore, we can conclude that names for given phase changes A and B is that A is condensation and B is freezing.

3 0

4 years ago

Read 2 more answers

What is the boiling point of water at an elevation of 1.55×104 ft ?

horsena [70]

The computation for this problem is:
(1.55x10^4 / 1.0x10^3) x 19.8 mm Hg
= 15.5 x 19.88 mm Hg
= 308.14 mm Hg decrease
= 308.14 x 0.05 C = 15.407 deg C
deduct this amount to 100
100 – 15.407 = 84.593 C
ANSWER: 85 deg C (rounded to 2 significant figures)

4 0

3 years ago