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3 years ago

How many moles are in 563.9 grams of arsenic?

Chemistry

1 answer:

Aleks [24]3 years ago

6 0

Answer:

No. of moles, n = 7.52 moles

Explanation:

Given that,

Mass, m = 563.9 grams

Molar mass of arsenic = 74.92 g/mol

We need to find the number of moles in 563.9 grams of arsenic. Let it is denoted by n. It is equal to given mass divided by total molar mass.

$n=\dfrac{563.9 }{74.92}\\\\=7.52\ \text{moles}$

So, there are 7.52 moles in 563.9 grams of arsenic.

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A hamburger containing 335.4 kcal of energy was combusted in a bomb calorimeter with an unknown heat capacity. The temperature o

Zielflug [23.3K]

Answer:

$Cv_{calorimeter}=18.4kcal/K$

Explanation:

Hello!

In this case, since the combustion of the hamburger released 335.4 kcal of energy and that energy is received by the calorimeter, we can write:

$Q_{hamburguer}=-Q_{calorimeter}$

And the heat of the calorimeter is written in terms of the temperature change and the calorimeter constant:

$Q_{hamburguer}=-Cv_{calorimeter}\Delta T$

Thus, given the released heat by the hamburger due to its combustion and the temperature change, Cv for the calorimeter turns out:

$Cv_{calorimeter}=\frac{-Q_{hamburguer}}{\Delta T} =\frac{-(-335.4kcal)}{18.2K}\\\\Cv_{calorimeter}=18.4kcal/K$

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3 years ago

Changing subscripts is one of the steps of balancing a chemical equation.<br> True or False

Lostsunrise [7]

Answer:

False

Explanation:

Changing the coefficients is one of the steps of balancing a chemical equation. Changing the subscript changes the compounds being used, while changing the coefficient changes the amount of each compound being used.

3 0

3 years ago

Read 2 more answers

A compound is formed when 12.2 g Mg combines completely with 5.16 g N. What is the percent composition of this compound? Please

STALIN [3.7K]

3Mg + N₂= Mg₃N₂
n(Mg)=12,2g÷<span>24,4g/mol=0,5mol-limiting reagent
</span>n(N₂)=5,16g÷28g/mol=0,18mol
n(Mg₃N₂):n(Mg)=1:3, n(Mg₃N₂)=0,166mol, m(Mg₃N₂)=0,166·101,2=16,8g.
%(N)= 2·Ar(N)÷Mr(Mg₃N₂) = 2·14÷101,2=27,66%=0,2766
%(Mg) = 3·Ar(Mg)÷Mr(Mg₃N₂)= 3·24,4÷101,2=72,34% or 100% - 27,66%= 72,34%.

4 0

3 years ago

On average, Earth’s crust contains about 8.1% aluminum by mass. If a standard 12-ounce soft drink can contains approximately 15

MrMuchimi

Answer:

5400 cans

Explanation:

First we convert the total weight, 1 ton, to grams:

$1ton=1x10^{6}g$