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MariettaO [177]
3 years ago
9

Mass of 60.009 g and radius of 1.02 cm what is the density of the sphere in (g/ml)

Chemistry
1 answer:
alexandr402 [8]3 years ago
4 0
Density is given as mass / volume.

Mass is the sphere is 100 g.

Volume of the sphere = (pi∗r3)∗4/3
(
p
i
∗
r
3
)
∗
4
/
3

=(4∗22∗3∗3∗3)/(7∗3)cm3
=
(
4
∗
22
∗
3
∗
3
∗
3
)
/
(
7
∗
3
)
c
m
3

=792/7
=
792
/
7
cm3
3

Therefore, Density is 100/(792/7)g/cm3
100
/
(
792
/
7
)
g
/
c
m
3

Which gives: density = 0.883838 g/cm3
g
/
c
m
3

If you want to change the units to kg per cubic metres, then we need to divide this value by 1000( for g to kg) and multiply by 100 * 100 * 100 (for cm to m).

This makes the density to be 883.83 kg/m3
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Calculate the percentage of each element in acetic acid, hc2h3o2, and glucose, c6h12o6.
My name is Ann [436]
<em>Acetic acid, HC2H3O2</em>

First, calculate for the molar mass of acetic acid as shown below.
    M = 1 + 2(12) + 3(1) + 2(16) = 60 g

Then, calculating for the percentages of each element.
<em> Hydrogen:</em>
    P1 = ((4)(1)/60)(100%) = <em>6.67%</em>

<em> Carbon:</em>
   P2 = ((2)(12)/60)(100%) = <em>40%</em>

<em>Oxygen</em>
  P3 =((2)(16) / 60)(100%) = <em>53.33%</em>

<em>Glucose, C6H12O6</em>

The molar mass of glucose is as calculated below,
   6(12) + 12(1) + 6(16) = 180

The percentages of the elements are as follow,
 <em> Hydrogen:</em>
   P1 = (12/180)(100%) = <em>6.67%</em>

<em>Carbon:</em>
  P2 = ((6)(12) / 180)(100%) = <em>40%</em>

<em>Oxygen:</em>
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b. Since the empirical formula of the given substances are just the same and can be written as CH2O then, the percentages of each element composing them will just be equal. 
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3 years ago
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AysviL [449]

Answer:

(a) The rate of formation of K2O is 0.12 M/s.

The rate of formation of N2 is also 0.12 M/s

(b) The rate of decomposition of KNO3 is 0.24 M/s

Explanation:

(a) From the equation of reaction, the mole ratio of K2O to O2 is 2:5.

Rate of formation of O2 is 0.3 M/s

Therefore, rate of formation of K2O = (2×0.3/5) = 0.12 M/s

Also from the equation of reaction, mole ratio of N2 to O2 is 2:5.

Rate of formation of N2 = (2×0.3/5) = 0.12 M/s

(b) From the equation of reaction, mole ratio of KNO3 to O2 is 4:5.

Therefore, rate of decomposition of KNO3 = (4×0.3/5) = 0.24 M/s

3 0
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A hydrogen bond can occur between:
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A hydrogen bond occurs between a hydrogen from one molecule and an oxygen from another molecule. Option D

<h3>What is the hydrogen bond?</h3>

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Thus, a hydrogen bond occurs between a hydrogen from one molecule and an oxygen from another molecule. Option D

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