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Orlov [11]
3 years ago
15

Answer all questions pls

Chemistry
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

1) The cryosphere contains the frozen parts of the planet. This sphere helps maintain Earth's climate by reflecting incoming solar radiation back into space. As the world warms due to increasing greenhouse gases being added to the atmosphere by humans, the snow and ice are melting.

2) Organisms like the Frilled Shark, Giant Spider Crab. Atlantic Wolffish Pair, Fangtooth Fish, Six-Gill Shark, Giant Tube Worms, Vampire Squid, Pacific Viperfish. But there are most likely archaeabacteria which are prokaryotic bacteria or single-celled organisms. A Prokaryotic cell does not contain a nucleus. It only contains one chromosome and is a single-celled organism. It was the only form of life on earth for millions of years. Examples of a Prokaryotic cell are the different types of bacteria present today.

3) Many different types of plant and animal communities call estuaries home because their waters are typically brackish — a mixture of fresh water draining from the land and salty seawater. This unique combination of salty and fresh water creates a variety of habitats. Estuaries are full of decaying plants and animals. This makes the soil of estuaries rich in nutrients. Because the soil is so rich, lots of different plants grow in estuaries. The plants attract lots of different animals to the estuary and those animals attract other animals to the estuary.

4) Temperature, humidity, precipitation, air pressure, wind speed, and wind direction are key observations of the atmosphere that help forecasters predict the weather. These same factors have been used since the first weather observations were recorded. Observational data collected by doppler radar, radiosondes, weather satellites, buoys and other instruments are fed into computerized NWS numerical forecast models. The models use equations, along with new and past weather data, to provide forecast guidance to our meteorologists. The three main factors of weather are light (solar radiation), water (moisture) and temperature.

Explanation:

U dont have to copy and paste this put these are some ideas to use for ur answers

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Which statement is true of phenolphthalein?
Anna007 [38]

The correct option is B.

Phenophtalein is an indicator that is usually used in acid base titration experiments. Indicators are substances that undergo distinct, observable changes when the pH of their solutions change. Indicators exhibit changing of colors depending on the pH of the solution in which they are found. They are usually weak bases and acid which are capable of partial dissociation and formation of ions when dissolved in water. There are different types of indicator and phenophtalein is one of them. Phenophtalein is colorless in acidic solution and pink in basic solutions.

5 0
3 years ago
Read 2 more answers
What does the octet rule have to deal with covalent bonds
irga5000 [103]
<span>Rule of the octet is used in chemistry to indicate the tendencies of the atoms when they complete the energy level to obtain stability. Covalent bonds are what occurs when two atoms join and reach the stable octet. They are related because through this union electrons are shared and the covalent bond is produced and the rule of the octet is given to show the tendency of this union.</span>
6 0
3 years ago
A reaction produces 0.861 moles of H2O . How many molecules of H2O are produced?
ioda

Answer:

5.19 x 10²³ molecules of H₂O

Explanation:

1 mole => 6.023 x 10²³ molecules of H₂O

0.861 mole => 0.861mole x 6.023 x 10²³ molecules of H₂O

= 5.19 x 10²³ molecules of H₂O

4 0
3 years ago
Which of the following examples best represent the levels of organization from least to most complex in humans
Anika [276]
I’d say C not sure though
5 0
2 years ago
Calculate the molality of a 10.0% by mass solution of NaCl ______ m
Lubov Fominskaja [6]

Answer:

\large \boxed{\text{0.180 mol/kg }}

Explanation:

Assume 100 g of solution.

Then you have 10.0 g of NaCl and 90.0 g of water.

\text{Molal concentration} = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}

1. Moles of NaCl

\text{Moles of NaCl} = \text{10.0 g NaCl} \times \dfrac{\text{1 mol NaCl}}{\text{58.44 g NaCl}} = \text{0.1711 mol NaCl}

2. Kilograms of water

\text{Kilograms} = \text{90.0 g} \times \dfrac{\text{1 kg}}{\text{1000 g}} = \text{0.0900 kg}

3. Molal concentration

\text{Molal concentration} = \dfrac{\text{0.1711 mol}} {\text{0.0900 kg}} = \textbf{1.90 mol/kg}\\\\\text{The molal concentration of the solution is $\large \boxed{\textbf{0.180 mol/kg }}$}

5 0
3 years ago
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