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worty [1.4K]
3 years ago
13

How many molecules are in 67.0 grams of potassium chloride KCl

Chemistry
1 answer:
valentinak56 [21]3 years ago
8 0
67g KCl(1 mol KCl/74.55g)=0.8987256875 mol KCl
0.8987256875 mol KCl(6.02*10^23 molecules/ 1 mol)
=5.410328638*10^23 molecules KCl
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How many milliliters of a 0.275 M NaOH solution is required to react with 0.450 L of CO2 gas
padilas [110]

Volume of NaOH required to react = 145.5 ml

<h3>Further explanation</h3>

Reaction

CO₂(g) + 2 NaOH(aq)  ⇒Na₂CO₃(aq) + H₂O(l)

The volume of CO₂ : 0.45 L

mol CO₂ at STP (O C, 1 atm) ⇒ at STP 1 mol gas 22.4 L :

\tt mol~CO_2=\dfrac{0.45}{22.4}=0.02

From the equation, the mol ratio of CO₂ : NaOH = 1 : 2, so mol NaOH :

\tt mol~NaOH=\dfrac{2}{1}\times 0.02=0.04

Then volume of NaOH :

\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.04}{0.275}\\\\V=0.1455~L\rightarrow 145.5~mL

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3 years ago
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Explanation:

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