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BlackZzzverrR [31]
3 years ago
13

What is the relationship between force in velocity selector in a bain bridge.​

Physics
1 answer:
kifflom [539]3 years ago
4 0

Answer:

In a velocity selector, there are two forces namely;

» Electric field Intensity

» Magnetic field density

<u>Relationship</u><u>:</u>

E _{e}= B

E is the electric field intensity

B is the magnetic flux density

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A race car has a centripedal acceleration of 13.33M/S as it goes around a curve. If the curve is a circle with radius 30 m, what
agasfer [191]

Answer:19.997m/s

Explanation:

Velocity=√(centripetal acceleration×radius)

Velocity=√(13.33×30)

Velocity=√(399.9)

Velocity=19.997

8 0
3 years ago
a ball of mass 0.5 kg moving at 10 m/s collides with another ball of equal mass at rest. if the two balls move off together afte
nexus9112 [7]

Answer:

5 m/s

Explanation:

Here we can see there is no external force acted on a two masses when we consider the motion. If there is no external forces then momentum is conserved.

Initial momentum = Final momentum

0.5 × 10  = 1 × V

V = 5 m/s

7 0
3 years ago
Six artificial satellites circle a space station at a constant speed. The mass m of each satellite, distance L from the space st
damaskus [11]

Answer:

The answer to the question is;

Based on their acceleration the rank of the satellites from largest to smallest is.

B   >→   A   >→    E   >→    C    >→     F    >→     D.

Explanation:

Acceleration is given by \frac{v^2}{r}

Therefore the acceleration for each of the satellite is given by

Satellite A)      \frac{160^2}{5000} =    5.12 m/s²

Satellite B)      \frac{160^2}{2500}  =   10.24 m/s²

Satellite C)      \frac{80^2}{2500}   =  2.56 m/s²

Satellite D)      \frac{40^2}{10000}  =  0.16 m/s²

Satellite E)       \frac{120^2}{5000}   =  2.88 m/s²

Satellite F)       \frac{80^2}{10000}  = 0.64 m/s²

Therefore in order of decreasing acceleration, from largest to smallest we have

Satellite B) > Satellite A) >Satellite E) >Satellite C)>Satellite F)>Satellite D).

3 0
3 years ago
Read 2 more answers
_________ light is unique in that it vibrates mostly in one direction.
Misha Larkins [42]

Polarized light light is unique in that it vibrates mostly in one direction.

Polarized mild waves are light waves in which the vibrations occur in a single plane. The process of reworking unpolarized light into polarized light is called polarization. There are a ramification of methods of polarizing mild.

Polarization is used for differentiating among transverse and longitudinal waves. Infrared spectroscopy makes use of polarization. it is used in seismology to take a look at earthquakes. In Chemistry, the chirality of organic compounds is tested the use of polarization strategies.

Refraction is the change in route of waves that takes place when waves tour from one medium to every other. . Light has a dual nature. as it has waves, sunlight passing via  rainstorm makes a rainbow. however, while mild moves a sun mobile, it can provide strength as a series of very small bursts. particles of count number have names together with the proton, electron and neutron.

Learn more about lights here:-brainly.com/question/19697218

#SPJ4

6 0
1 year ago
The engine starter and a headlight of a car are connected in parallel to the 12.0-V car battery. In this situation, the headligh
stepladder [879]

Answer:

The total power they will consume in series is approximately 2.257 W

Explanation:

The connection arrangement of the headlight and the engine starter = Parallel to the battery

The voltage of the battery, V = 12.0 V

The power at which the headlight operates in parallel, P_{headlight} = 38 W

The power at which the kick starter operates in parallel, P_{kick \ starter} = 2.40 kW

We have;

P = V²/R

Where;

R = The resistance

V = The voltage = 12 V (The voltage is the same in parallel circuit)

For the headlight, we have;

R₁ = V²/P_{headlight}  = 12²/38 = 72/19

R₁ = 72/19 Ω

For the kick starter, we have;

R₂ = V²/P_{kick \ starter} = 12²/2.4 = 60

R₂ = 60 Ω

When the headlight and kick starter are rewired to be in series, we have;

Total resistance, R = R₁ + R₂

Therefore;

R = ((72/19) + 60) Ω = (1212/19) Ω

The current flowing, I = V/R

∴ I = 12 V/(1212/19) Ω = (19/101) A

We note that power, P = I²R

In the series connection, we have;

P_{headlight} = I² × R₁

∴ P_{headlight} = ((19/101) A)² × 72/19 Ω = 1368/10201 W ≈ 0.134 W

The power at which the headlight operates in series, P_{headlight, S} ≈ 0.134 W

P_{kick \ starter} = ((19/101) A)² × 60 Ω = 21660/10201 W ≈ 2.123 W

The power at which the kick starter operates in series, P_{kick \ starter, S} ≈ 2.123 W

The total power they will consume, P_{Total} = P_{headlight, S} + P_{kick \ starter, S}

Therefore;

P_{Total} ≈ 0.134 W + 2.123 W = 2.257 W

4 0
3 years ago
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