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satela [25.4K]
3 years ago
5

The area under acceleration time garph represents?​

Physics
2 answers:
Keith_Richards [23]3 years ago
8 0

Answer:

Change in Velocity because

at = v

Explanation:

Remeber area is length times Width. In this case, the area under a accleraton vs time graph is Accleration Times Time. Which is velocity

ioda3 years ago
3 0

Answer:

<h3>the area under acceleration time garph represents?</h3>

<em>The area under an acceleration graph represents <u>the change in velocity</u>. In other words, the area under the acceleration graph for a certain time interval is equal to the change in velocity during that time interval.</em>

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an object has 5.00 kg*m/s of momentum. if you double the mass and double the velocity, how much momentum would it have PLEASE HE
KIM [24]

The final momentum is 20.00 kg*m/s

Explanation:

The momentum of an object is given by:

p=mv

where

m is the mass of the object

v is its velocity

For the object in the problem, the initial momentum is

p=mv=5.00 kg m/s

Then, the mass is doubled:

m' = 2m

And the velocity is also doubled:

v' = 2v

So, the new momentum will be:

p'=m'v'=(2m)(2v)=4(mv) = 4p = 4(5.00)=20 kg m/s

So, the final momentum is 4 times the initial momentum.

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4 years ago
A sound signal traveling underwater has a frequency of 230 hertz. The speed of sound under water is 1. 45 × 103 meters/second. W
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Answer:

A.6.3

Explanation:

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3 years ago
The Earth's magnetic field is approximately 0.5 Gauss. What is the magnetic energy density of this field
ser-zykov [4K]

Answer:

The  magnetic energy density  is  E_B  =  9.95 *10^{-4} \  J/m^3

Explanation:

From the question we are told that  

    The  earths magnetic field is  B  =  0.5 \  Gauss

Now

          1 \ Gauss  \to  1 *10^{-4} \ T

=>        0.5  \ Gauss  \to  x T

So  

          x =  \frac{0.5 *  1*10^{-4}}{1}

          x = B= 5.0 *10^{-5} \  T

Generally the magnetic energy density is  mathematically represented as

        E_B  =  \frac{B^2}{ 2 *  \mu_o  }

  Here \mu_o is the  permeability of  free space with a constant value

          \mu_o  =  4\pi * 10^{-7} N/A^2

substituting values for equation above  

       E_B  =  \frac{(5*10^{-5})^2}{ 2 *   4\pi * 10^{-7}  }

       E_B  =  9.95 *10^{-4} \  J/m^3

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3 years ago
When all individual forces acting upon an object are balanced, it is the natural tendency of the object to
sleet_krkn [62]

Answer:

- maintain its state of motion

- Keep its velocity constant (either at zero or non-zero value)

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Studies of the relationship of the Sun to our galaxy-the Milky Way-have revealed that the Sun is located near the outer edge of
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Mass of the milkyway galaxy :

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The magnitude of the mass of the Milky Way galaxy = 2.7x10^{14} Kg

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