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satela [25.4K]
2 years ago
5

The area under acceleration time garph represents?​

Physics
2 answers:
Keith_Richards [23]2 years ago
8 0

Answer:

Change in Velocity because

at = v

Explanation:

Remeber area is length times Width. In this case, the area under a accleraton vs time graph is Accleration Times Time. Which is velocity

ioda2 years ago
3 0

Answer:

<h3>the area under acceleration time garph represents?</h3>

<em>The area under an acceleration graph represents <u>the change in velocity</u>. In other words, the area under the acceleration graph for a certain time interval is equal to the change in velocity during that time interval.</em>

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44.2 cm + 0.123 cm = cm
trapecia [35]
The answer is 44.323 cm
3 0
3 years ago
Read 2 more answers
If a thermometer measured the temperature in an oven as 400oF five days in a row when the temperature was actually 397oF, this m
aleksandrvk [35]

Answer:

It can be said to be reliable although it is not valid

Explanation:

This is because Reliability means an indicator of consistency, A measure should produce similar or the same results consistently if it measures the same quantity. So does the thermometer measures over 5days but it is not valid because it deviates from the real value

5 0
3 years ago
Si un ciclista se mueve a una velocidad de 5 m/s y acelera 1 m/s2, a los 10 segundos su velocidad será
MrRa [10]

Answer:

A los 10 segundos su velocidad será 15 \frac{m}{s}

Explanation:

La aceleración de un objeto es una magnitud que indica cómo cambia la velocidad del objeto en una unidad de tiempo.

En otras palabras, la aceleración relaciona los cambios de la velocidad con el tiempo en el que se producen, es decir que mide cómo de rápidos son los cambios de velocidad:

  • Una aceleración grande significa que la velocidad cambia rápidamente.
  • Una aceleración pequeña significa que la velocidad cambia lentamente.
  • Una aceleración cero significa que la velocidad no cambia.

La aceleración "a" puede ser calculada mediante la expresión:

a=\frac{vfinal - vinicial}{tiempo}

En este caso:

  • a= 1 \frac{m}{s^{2} }
  • vfinal= ?
  • vinicial= 5 \frac{m}{s}
  • tiempo= 10 s

Reemplazando:

1\frac{m}{s^{2} }=\frac{vfinal - 5\frac{m}{s} }{10 s}

Resolviendo se obtiene:

1 \frac{m}{s^{2} } *10 s= vfinal - 5 \frac{m}{s}

10 \frac{m}{s} = vfinal - 5 \frac{m}{s}

10 \frac{m}{s} + 5 \frac{m}{s} = vfinal

15 \frac{m}{s} = vfinal

<u><em>A los 10 segundos su velocidad será 15 </em></u>\frac{m}{s}<u><em></em></u>

5 0
2 years ago
A 57 kg wagon is pulled with a constant net force of 38 N. Calculate the acceleration of the wagon. F = ma
Dahasolnce [82]

Answer:

<h2>0.67 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{38}{57} =  \frac{2}{3}   \\  = 0.666666...

We have the final answer as

<h3>0.67 m/s²</h3>

Hope this helps you

4 0
3 years ago
Semi-trailer trucks have an odometer on one hub of a trailer wheel. The hub is weighted so that it does not rotate, but it conta
shtirl [24]

Answer:

1020 km

Explanation:

A complete rotation of the wheel equals a distance of 1 circumference.

The circumference is

C = \pi d

where <em>d</em> is the diameter of the wheel.

300,000 rotations = 300000\pi d = 300000\times\pi\times1.08\text{ m} = 1017876.0\ldots\text{ m}

In kilometers, this is = 1017876/1000 km = 1020 km

6 0
3 years ago
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