The marching l meaning of the X intercept is when the school receives $0
Answer:
1.5 bars of granola per student
Step-by-step explanation:
Number of students = 4
Number of granola bars = 6
Four students share 6 granola bars equally.
Each student gets = 6 ÷ 4
= 1 1/2
= 1.5 bars of granola per student
Each student's share is 1.5 granola bars.
Answer:
20
Step-by-step explanation:
x/2+15=25
x/2=10
x=20
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Step-by-step explanation:
78 = 2 * 39 = 2 * 3 * 13.
Since 6 = 2 * 3 and its factors can be found in 78,
Hence the answer is 6. (C)
Answer:
![the \: area \: of \: the \: logo \: is \: {91cm}^{2}](https://tex.z-dn.net/?f=the%20%5C%3A%20area%20%5C%3A%20of%20%5C%3A%20the%20%5C%3A%20logo%20%5C%3A%20is%20%5C%3A%20%20%7B91cm%7D%5E%7B2%7D%20)
Step-by-step explanation:
To determine the area of the logo you have to calculate the area of the triangle and the square that comform it and then add the four areas.
Area of the square.
To calculate the area of the square you have to calculate the square of one of its sides, following the formula:
![a = {a}^{2}](https://tex.z-dn.net/?f=a%20%3D%20%20%7Ba%7D%5E%7B2%7D%20)
Where "a" is the length of one of its side.
The side length of the square is a=7cm, so its area will be:
![asquare = {7}^{2} \\ asquare = {49cm}^{2}](https://tex.z-dn.net/?f=asquare%20%3D%20%20%7B7%7D%5E%7B2%7D%20%20%5C%5C%20asquare%20%3D%20%20%7B49cm%7D%5E%7B2%7D%20)
Area of the triangles.
The three triangles are equal, they have a base equal to the side of the square, i.e. with a length of 7cm, and their height is h=4cm.
To calculate the area of one triangle, you have to multiply its base by its height and divide by 2, following the formula:
![a = \frac{b.h}{2} \\ a = \frac{7.4}{2} \\ a = \frac{28}{2} \\ a = {14cm}^{2}](https://tex.z-dn.net/?f=a%20%3D%20%20%5Cfrac%7Bb.h%7D%7B2%7D%20%20%5C%5C%20%20a%20%3D%20%20%5Cfrac%7B7.4%7D%7B2%7D%20%20%5C%5C%20a%20%3D%20%20%5Cfrac%7B28%7D%7B2%7D%20%20%5C%5C%20a%20%3D%20%20%7B14cm%7D%5E%7B2%7D%20)
The area calculated the correspond to one triangle, since all triangles are congruent, you have to multiply the said area by 3 to determine the area of three figures:
![atriangles = 3a \\ atriangles = {42cm}^{2}](https://tex.z-dn.net/?f=atriangles%20%3D%203a%20%5C%5C%20atriangles%20%3D%20%20%7B42cm%7D%5E%7B2%7D%20)
Now that the area of all shape are calculated, you have to add them to determine the area of the logo:
![alogo = asquare + atriangle \\ alogo = 49 + 42 \\ alogo = {91cm}^{2}](https://tex.z-dn.net/?f=alogo%20%3D%20asquare%20%2B%20atriangle%20%5C%5C%20alogo%20%3D%2049%20%2B%2042%20%5C%5C%20alogo%20%3D%20%20%7B91cm%7D%5E%7B2%7D%20)