<span>Concentration of a chemical in a solution refers to how many of the chemical's molecules are sitting in a small volume of the solution. Concentration could be measured in molecules per liter, although molecules are so small compared to a liter that we usually use different units (just like we wouldn't want to measure the distance between the earth and the sun in inches). A gradient is a measurement of how much something changes as you move from one region to another. So a concentration gradient is a measurement of how the concentration of something changes from one place to another.
If this doesn't help here's a Khan Academy video </span><span>https://www.khanacademy.org/...and.../concentration-gradients</span>
From the calculations, the heat of the reaction is 44.4 kJ/mol.
<h3>What is the enthalpy of reaction?</h3>
The enthalpy of reaction refers to the amount of heat that is absorbed or evolved in a reaction.
Number of moles of NaOH = 1.1 g /40 g/mol = 0.0275 moles
Mass of the water = 22.1 mL or 22.1 g
Given that;
H= mcdT
H = 22.1 g *4.184 * (31.4 - 18.2)
H = 1221 J or 1.221kJ
ΔH rxn = -(1.221kJ)/0.0275 moles
ΔH rxn = 44.4 kJ/mol
Learn more about enthalpy:brainly.com/question/15319033
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Answer:
4752 ft/min.
Explanation:
The following data were obtained from the question:
Speed (in mph) = 54 mph
1 mile = 5280 feet
1 hour = 60 minutes
Speed ( in ft/min) =?
Next, we shall convert 54 mph to ft/h. This can be obtained as follow:
1 mph = 5280 ft/h
Therefore,
54 mph = 54 mph × 5280 ft/h / 1 mph
54 mph = 285120 ft/h
Finally, we shall convert 285120 ft/h to ft/min. This can be obtained as follow:
1 ft/h = 1/60 ft/min
Therefore,
285120 ft/h = 285120 ft/h × 1/60 ft/min / 1 ft/h
285120 ft/h = 4752 ft/min
From the calculations made above, 54 mph is equivalent to 4752 ft/min.
Answer:
cytosol
Explanation:
hope it help sorry if it is wrong
Answer is: mass of the ore is 8.54kg.<span>
</span>ω(Ca₃(PO₄)₂ - calcium phosphate) = 58.6% ÷ 100% = 0.586.
m(P) = 1.00 kg · 1000 g/kg.
m(P) = 1000 g.
In one molecule of calcium phosphate there are two phosphorus atoms:
M(Ca₃(PO₄)₂) = 310.18 g/mol.
M(P) = 30.97 g/mol.
For one kilogram of phosphorus, we need:
M(Ca₃(PO₄)₂) : 2M(P) = m(Ca₃(PO₄)₂) : m(P).
310.18 g/mol : 61.94 g/mol = m(Ca₃(PO₄)₂) : 1000 g.
m(Ca₃(PO₄)₂) = 5007.75 g ÷ 1000 g/kg = 5.007 kg.
Mass of ore find from proportion:
m(Ca₃(PO₄)₂) : m(ore) = 56% : 100%.
m(ore) = 100% · 5.007 kg ÷ 58.6%.
m(ore) = 8.54kg.