1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sholpan [36]
3 years ago
13

If a particular ore contains 58.6 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp

horus?
Chemistry
1 answer:
rjkz [21]3 years ago
5 0
Answer is: mass of the ore is 8.54kg.<span>

</span>ω(Ca₃(PO₄)₂ - calcium phosphate) = 58.6% ÷ 100% = 0.586.
m(P) = 1.00 kg · 1000 g/kg.
m(P) = 1000 g.
In one molecule of calcium phosphate there are two phosphorus atoms:
M(Ca₃(PO₄)₂) = 310.18 g/mol.
M(P) = 30.97 g/mol.
For one kilogram of phosphorus, we need:
M(Ca₃(PO₄)₂) : 2M(P) = m(Ca₃(PO₄)₂) : m(P).
310.18 g/mol : 61.94 g/mol = m(Ca₃(PO₄)₂) : 1000 g.
m(Ca₃(PO₄)₂) = 5007.75 g ÷ 1000 g/kg = 5.007 kg.
Mass of ore find from proportion:
m(Ca₃(PO₄)₂) : m(ore) = 56% : 100%.
m(ore) = 100% · 5.007 kg ÷ 58.6%.
m(ore) = 8.54kg.

You might be interested in
Determine the electron geometry (eg), molecular geometry (mg), and polarity of SO2. Determine the electron geometry (eg), molecu
Temka [501]

Answer:

See explaination

Explanation:

The electrons geometry shows the special distribution of the electrons around of the central atom of the molecule.

The molecular geometry shows the special distribution of the atoms that form the molecule.

Please kindly check attachment for further solution.

6 0
3 years ago
Use the following image to answer the following questions. A student was performing an experiment using two identical cups made
Anettt [7]

Answer:

The water will eventually become the same temature (A)

3 0
2 years ago
Determine the value of the equilibrium constant, Kgoal, for the reaction C(s)+12O2(g)+H2(g)⇌12CH3OH(g)+12CO(g), Kgoal=? by makin
Licemer1 [7]

Answer:

1.71x10²⁷

Explanation:

If we sum 1/2 of (3) + 1/2 of (1):

1/2 (3.) C(s) + 1/2O₂(g) ⇌ CO(g), K₃ = √2.10×10⁴⁷  = 4.58x10²³

1/2 (1)   1/2CO₂(g) + 3/2H₂(g) ⇌ 1/2CH₃OH(g) + 1/2H₂O(g), K₁ = √1.40×10² = 11.8

C(s) + 1/2O₂(g) +<u> 1/2CO₂(g) </u>+<u> 3/2H₂(g</u>) ⇌ 1/2CH₃OH(g) + <u>1/2H₂O(g)</u> + <u>CO(g)</u>

K' = 4.58x10²³ * 11.8 = 5.42x10²⁴

+1/2 (2):

<u>1/2 CO(g)</u> +<u> 1/2H₂O(g)</u> ⇌<u> 1/2CO₂(g)</u> + <u>1/2H₂</u> (g), K = √1.00×10⁵ = 316.2

C(s) + 1/2O₂(g) + H₂(g) ⇌ 1/2 CHO₃H(g) + 1/2CO(g)

K'' = 5.42x10²⁴* 316.2 =

<h3>1.71x10²⁷</h3>

5 0
3 years ago
Carbon hexafluroide formula
ikadub [295]

The formula for Hexafluoride is F6S.

4 0
3 years ago
In yeast, ethanol is produced from glucose under anaerobic conditions. A cell‑free yeast extract is placed in a solution that co
nadezda [96]

Answer:

0.35 milli moles of ethanol can be theoretically be produced under these conditions.

Explanation:

C_6H_{12}O_6 + 2 ADP + 2 Pi\rightarrow 2 C_2H_5OH + 2 ATP + 2 CO_2

Moles of glucose = 3.50\times 10^2 milli mole

Moles of ADP = 0.35 milli mole

Moles of Pi = 0.35 milli mole

Moles of ATP = 0.70 milli mole

As we can see that ADP and Pi are in limiting amount which means tat they are limiting reagent. So, the moles of ethanol produced will depend upon the moles of ADP and Pi.

According to reaction, 2 moles of ADP gives 2 moles of glucose.

Then 0.35 milli moles of ADp will give :

\frac{2}{2}\times 0.35 mmol=0.35 mmol of ethanol

0.35 milli moles of ethanol can be theoretically be produced under these conditions.

5 0
3 years ago
Other questions:
  • Before you touch an electrical switch, plug, or outlet
    15·2 answers
  • A 111.6 gram sample of iron (MW=55.8) was heated from 0 degrees C to 20 degrees C. It absorbed 1004 Joules of energy. What is th
    9·1 answer
  • Which statement accurately describes the rock layers
    10·1 answer
  • If a ballon at 3.4 atm at 301k, what is the pressure when cooled to 212k
    10·1 answer
  • Why is creativity important in constructing scientific explanations?
    6·1 answer
  • A physician orders a patient to receive 1.25 mg of conjugated estrogen per day you have conjugated estrogens and 0.625 mg tablet
    14·1 answer
  • Activation energy Group of answer choices is only required in catabolic reactions that release energy. is not required at all wh
    12·1 answer
  • Indicar la cantidad de sustancia en: a) 2.0L de un gas en C.N; b) 22.4 mL de un gas a 755 torr y 26 grados celsius?
    5·1 answer
  • What type of reaction is Fe+H2O=Fe3O4+H2
    11·2 answers
  • Which one is more acidic, Chloroacetic acid or Bromoacetic acid? And why?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!