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ddd [48]
2 years ago
7

A marble is L 1.32 W 1.32 H 1.32, what is the volume? Show your work

Chemistry
1 answer:
cupoosta [38]2 years ago
6 0

The volume of the marble is 2.3 cube units.

From the question given above, the following data were obtained:

  • Length (L) = 1.32
  • Width (W) = 1.32
  • Height (H) = 1.32
  • Volume (V) =?

The volume of the marble can be obtained as follow:

V = L × W × H

V = 1.32 × 1.32 × 1.32

V = 2.3 cube units

Thus, the volume of the marble is 2.3 cube units.

Learn more about volume:

brainly.com/question/20665757

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A 65.0-gram sample of some unknown metal at 100.0° C is added to 100.8 grams of water at 22.0° C. The temperature of the water r
vampirchik [111]
We do a heat balance to solve this:
(m cp ΔT)water = -(m cp ΔT)metal
100.8 (4.18) (27 - 22) = -65 (cp)(27-100)
cp = 100.8 (4.18) (27 - 22) / (-65 (27-100))
cp = 0.44 J/ (°C × g)

The specific heat of the metal is 0.44 J/ (°C × g)
5 0
3 years ago
What is the molarity of a solution that is made by mixing 35.5 g of Ba(OH)2 in 325 ml of solution?
choli [55]

Answer:

M=0.638M

Explanation:

Hello!

In this case, since the molarity of a solution is calculated by diving the moles of solute by the volume of solution in liters, we first compute the moles of barium hydroxide in 35.5 g as shown below:

n=35.5g Ba(OH)_2*\frac{1molBa(OH)_2}{171.34gBa(OH)_2}\\\\n=0.207mol

Then, the liters of solution:

V=325mL*\frac{1L}{1000mL} =0.325L

Finally, the molarity turns out:

M=\frac{0.207mol}{0.325L}\\\\M=0.638M

Best regards!

5 0
3 years ago
Lab activity - Law of Conservation of Mass with vinegar and baking soda.
lesya [120]

Answer: I BIG DUMB

Explanation:

7 0
2 years ago
Solution A has a pH of 10, and solution B has a pH of 1. Which statement best describes these solutions?
Free_Kalibri [48]

Answer:

Solution A is a Weak Alkali, Solution B is a strong Acid.

Explanation:

At pH 10, the colour is blue, therefore it's a weak alkali.

At pH 1, the colour is red, therefore it's a strong Acid.

7 0
3 years ago
A sample has a mass of 35.4g and a volume of 36.82mL. What is the density of the sample
vredina [299]

The density of the sample is 0.96 g/mL.


Density is found by dividing the mass of an object by its volume.


D=m÷v

D=35.4 g÷36.82 mL

D=0.96 g/mL

6 0
2 years ago
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