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Tpy6a [65]
3 years ago
13

PLZZ HELP!! If light traveling through air is then passed through glass, what is the result?

Chemistry
1 answer:
Radda [10]3 years ago
5 0

Answer : The light rays are bent and refraction will occur - B.

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Is the answer B? Help
Masja [62]

Answer:

A

Explanation:

Hmm, so we have the following in the diagram

Pt(s)

Cl2(g)

Ag(s)

NaCl(aq)

AgNO3(aq)

Pt 2+, 4+, 6+  Though it states Pt is inert

Cl 2-

Ag 1+

Na 1+

NO3-

Anode definition: the positively charged electrode by which the electrons leave an electrical device.

Electrode definition: a conductor through which electricity enters or leaves an object, substance, or region.

Cations attracted to cathode pick up electrons

Anions attracted to anode release electrodes+

Reduction at Cathode (red cat gain of e)

Oxidation at Anode (ox anode loss of e)

So from the diagram we can see that the charge is being generated through the 2 metal plates.

So the answer is A, the anode material is Pt and the half reaction is 2Cl- = Cl2 + 2e-

7 0
3 years ago
Law of Conservation of Mass in terms of atoms
VARVARA [1.3K]

No atoms are lost or made during the chemical reaction so the total mass of the products is equal to the total mass of the reactants. In an atom, protons and neutrons contribute to the mass and since the number of them doesn’t change, the mass doesn’t either.

4 0
3 years ago
C. Neither a Physical or Chemical Changu
Nutka1998 [239]

Explanation:

I think B a chemical change

5 0
3 years ago
The daily production of carbon dioxide from an 780.0 mw coal-fired power plant is estimated to be 3.3480 x 104 tons (not metric)
valkas [14]

The production of CO_{2} is 3.3480\times 10^{4} tons/day. Converting mass into kg,

1 ton=907.185 kg, thus,

3.3480\times 10^{4} tons=3.037\times 10^{7} kg

Thus, production of CO_{2} will be 3.037\times 10^{7} kg/ day.

The specific volume of CO_{2} is 0.0120 m^{3}/kg.

Volume of CO_{2} produced per day can be calculated as:

V=Specific volume\times mass

Putting the values,

V=0.0120 m^{3}/kg\times 3.037\times 10^{7} kg=364440 m^{3}/day

Thus, volume of CO_{2} produced per year will be:

V=\frac{365 days}{1 year}(364440 m^{3}/day)=1.33\times 10^{8}m^{3}/year

Thus, in 4 year volume of CO_{2} produced will be:

V=1.33\times 10^{8}m^{3}/year\times 4 years=5.32\times 10^{8}m^{3}

8 0
3 years ago
HELP! ASAP! Iron (Fe) and copper (II) chloride (CuCl2) combine to form iron (III) chloride (FeCl3) and copper (Cu). If you start
Helga [31]

Answer: 30.978

Explanation:

From the equation 2 moles of Fe will result in 3 moles copper

so .325 moles Fe will result in .4875 moles Cu

Cu weights 63.546 gm per mole

.4875 moles * 63.546 gm / mole = 30.978 gm of Cu

7 0
2 years ago
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