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Reika [66]
2 years ago
14

Write a balanced chemical equation for the incomplete combustion of methane to produce CO(g) as the only carbon-containing produ

ct.
Chemistry
1 answer:
Brums [2.3K]2 years ago
8 0

Answer:

2CH4(g)+3O2(g)→2CO(g)+4H2O(g)

Explanation:

Start with methane (CH4) and the gas product CO. It is safe to assume that the remaining products and reactants are O2 and H2O. There we have an unbalanced equation CH4+O2->CO+H2O after which it can be balanced as above.

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</span>Oxidation of 1-propanol with <span>Na</span>₂<span>Cr</span>₂<span>O</span>₇<span> and sulfuric acid</span><span> gives propanal and o</span><span>xidation with </span>chromic acid<span> gives </span>propionic acid<span>.</span>
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Sodium dodecanoate is soluble in water even though it contains a large hydrophobic segment. How does this molecule interact with
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7 0
3 years ago
A process at constant T and P can be described as spontaneous if ΔG &lt; 0 and nonspontaneous if ΔG &gt; 0. Over what range of t
creativ13 [48]

Answer:

Incomplete question, it is lacking the data it makes reference. The missing data from Chegg is:

                              2 SO3(g)   →          2 SO2(g) + O2(g)

ΔHf° (kJ mol-1)  -395.7                        -296.8

S° (J K-1 mol-1)  256.8                         248.2              205.1

ΔH° =  kJ

S° =  J K⁻¹

Explanation:

The method to solve this problem calls for the use of the Gibbs standard free energy change:

ΔG = ΔrxnH - TΔSrxn

We know a reaction is spontaneous when ΔG is < 0, so to answer this question we need to solve for the temperature, T, at which ΔG becomes negative.

Now as mentioned in the hint, we need to determine  ΔrxnH and ΔSrxn, which are given by

ΔrxnH = ∑ ν x ΔfHº products - ∑ ν x ΔfHº reactants

where  ν  is the stoichiometric coefficient in the balanced chemical equation.

For ΔS we have likewise

ΔrxnS =  ∑ ν x ΔSº products - ∑ ν x ΔSº reactants

Thus,

ΔrxnH(kJmol⁻¹) =  2 x (-296.8) - 2 x ( -395.7 ) = 197.8 kJ

ΔrxnS ( JK⁻¹) = 2 x 248.2 + 205.1 - 2 x 256.8 = 187.9 JK⁻¹ = 0.1879 kJK⁻¹

So ΔG kJ =  197.8 - T(0.1879)

and the reaction will become spontaneous when the term  T(0.1879)  becomes greater that 197.8,

0 = 197.8 - 0.1879 T  ⇒ T = 1052 K

so the reaction is spontaneous at temperatures greater than 1052 K (780 ºC)

4 0
3 years ago
An exothermic reaction is conducted in an insulated calorimeter filled with water. The calorimeter is then sealed so that there
Vaselesa [24]
Answer: option <span>C. the total energy inside the calorimeter will decrease.
</span>

Justification:

The answer is a direct application of the first law of thermodynamic (the law of conservation of energy).

By telling that the t<span>he calorimeter is sealed so that there is no heat exchanged between the contents of the container and the surrounding air, the first law of thermodynamics implies that the total energy inside the calorimeter will not change.
</span>

<span>That statement, without adding any more is enough justification.
</span>

Regarding, the other statements, you can show they are true:

<span>A. the thermometer will show an increase in temperature.
</span><span>
</span><span>
</span><span>Since the reaction is exothermic, the heat released will increase the temperature inside the sealed calorimeter,which, of course, is shown by the termometer.
</span><span>
</span><span>
</span><span>
</span><span>B. The potential energy of the products will be lower than that of the reactants.
</span><span>
</span><span>
</span><span>In any exothermic reaction, the potential energy of the products is lower than that of the reactants, because the heat released is lost by the reactants when they react and transform into the products.
</span><span>
</span><span>
</span><span>D. The water increases in temperature as the reaction gives off heat</span>.

Sure. The heat cannot leave the sealed calorimeter, but the water inside the calorimeter will absorb that heat: the molecules of water will gain kinetic energy and so its temperature will be increase.

6 0
3 years ago
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