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Reika [66]
2 years ago
14

Write a balanced chemical equation for the incomplete combustion of methane to produce CO(g) as the only carbon-containing produ

ct.
Chemistry
1 answer:
Brums [2.3K]2 years ago
8 0

Answer:

2CH4(g)+3O2(g)→2CO(g)+4H2O(g)

Explanation:

Start with methane (CH4) and the gas product CO. It is safe to assume that the remaining products and reactants are O2 and H2O. There we have an unbalanced equation CH4+O2->CO+H2O after which it can be balanced as above.

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Se tiene una solución acuosa 2M de carbonato de potasio. Expresar su concentración en %p/v y Normalidad.
zepelin [54]

Answer:

Normalidad = 4N

%p/V = 27.6%

Explanation:

La solución 2M de carbonato de potasio contiene 2moles de carbonato por litro de solución. La normalidad son los equivalente de carbonato de potasio (2eq/mol) por litro de solución:

2moles * (2eq/mol) = 4eq / 1L = 4N

El porcentaje peso volumen es el peso de carbonato en gramos dividido en el volumen en mL por 100:

%p/V:

Masa K2CO3 -Masa molar: 138.205g/mol-

2moles * (138.205g/mol) = 276g K2CO3

Volumen:

1L * (1000mL/1L) = 1000mL

%p/V:

276g K2CO3 / 1000mL * 100

<h3>%p/V = 27.6%</h3>
6 0
3 years ago
Which scientist performed the cathode ray experiment leading to the discovery of electrons
SVETLANKA909090 [29]

The scientist that performed the cathode ray experiment leading to the discovery of electrons is J.J. Thomson.

<h3>What is a cathode ray?</h3>

A cathode ray is a tube that contains negatively charged electrode( that is the cathode) which emits electrons when heated at a low pressure.

The cathode ray was used by the scientist, J.J. Thomson to find the ratio of charge to mass (e/m) of the electrons.

Therefore, the scientist that performed the cathode ray experiment leading to the discovery of electrons is J.J. Thomson.

Learn more about electrons here:

brainly.com/question/11316046

#SPJ1

6 0
2 years ago
How many grams are in 3.14 x 1015 molecules of CO?
Vesnalui [34]

Answer:

Explanation:

Not Many

1 mol of CO has a mass of

C = 12

O = 16

1 mol = 28 grams.

1 mol of molecules = 6.02 * 10^23

x mol of molecules = 3.14 * 10^15        Cross multiply

6.02*10^23 x = 1 * 3.14 * 10^15             Divide by 6.02*10^23

x = 3.14*10^15 / 6.02*10^23

x = 0.000000005 mols

x = 5*10^-9

1 mol of CO has a mass of 28

5*10^-9 mol of CO has a mass of x                        Cross Multiply

x = 5 * 10^-9 * 28

x = 1.46 * 10^-7 grams

Answer: there are 1.46 * 10-7 grams of CO if only 3.14 * 10^15 molecules are in the sample

5 0
3 years ago
Which is true about all the different types of matter?
Marat540 [252]
Answer: 1. It is made up of the same basic particles

Matter is made up of atoms, molecules, and ions that cause it to have mass and volume. The different types of matter are made up of the same basic particles but differ on the molecular arrangement and energy the atoms contains that's why they appear differently and have different properties.
8 0
3 years ago
Calculate the adjusted retention times for both pentafluorobenzene and benzene if the elution time for unretained solute is 1.06
vovangra [49]

Answer:

Pentafluorobenzene: 11,92 min

Benzene: 12,14 min

Explanation:

<em>Retention time of pentafluorobenzene is 12,98 min and 13,20 min of benzene.</em>

The adjusted retention time is the time an analyte spends in the column not the stationary phase. As time of unretained solute is 1,06 min the adjusted retention time for an analyte is:

tr' = tr - 1,06min

For pentafluorobenzene:

tr' = 12,98min - 1,06min = <em>11,92 min</em>

For benzene:

tr' = 13,20 - 1,06min = <em>12,14 min</em>

<em></em>

I hope it helps!

3 0
3 years ago
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