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Jet001 [13]
4 years ago
12

Even though the neighborhood shown by the green star was not next to any of these fires, how was the neighborhood affected by th

em?
A)
The heat generated by these fires made the temperatures in the surrounding areas increase.


B)
The smoke produced by these fires were carried by strong winds and made the air hard to breathe.


C)
The chemicals that were released by these fires cleared out the air and improved overall visibility.


D)
The air around the neighborhood was cooled due to the fire sucking the heat out of the surrounding air.
Chemistry
2 answers:
iogann1982 [59]4 years ago
7 0
Im pretty sure the answers b

soldi70 [24.7K]4 years ago
4 0

Answer:

B

Explanation:

B is the only possible answer that makes much sence, smoke is very toxic and it makes it hard to breath and is bad for your lungs

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muminat

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C) polarizability

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C) London dispersion forces

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D)Kr

Question 4:

E) strong enough to hold molecules relatively close together but not strong enough to keep molecules from moving past each other

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sammy [17]

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Red litmus turns blue

Explanation:

Hope it helps

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Do you really get 7 years of bad luck if you crack a mirror :(
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What is the pH of a 0.40 M solution of C6H5COOH?
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3 years ago
Pu is a nuclear waste byproduct with a half-life of 24,000 y. What fraction of the 239Pu present today will be present in 1000 y
olya-2409 [2.1K]

Answer:

0.9715 Fraction of Pu-239 will be remain after 1000 years.

Explanation:

\lambda =\frac{0.693}{t_{\frac{1}{2}}}

A=A_o\times e^{-\lambda t}

Where:

\lambda= decay constant

A_o =concentration left after time t

t_{\frac{1}{2}} = Half life of the sample

Half life of Pu-239 = t_{\frac{1}{2}}=24,000 y[

\lambda =\frac{0.693}{24,000 y}=2.8875\times 10^{-5} y^{-1]

Let us say amount present of  Pu-239 today = A_o=x

A = ?

A=x\times e^{-2.8875\times 10^{-5} y^{-1]\times 1000 y}

A=0.9715\times x

\frac{A}{A_0}=\frac{A}{x}=0.9715

0.9715 Fraction of Pu-239 will be remain after 1000 years.

7 0
3 years ago
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