(a) * (a+1) = 420
a^2 + a = 420
a^2 + a - 420 = 0
(a+21)(a-20) = 0
a = -21 OR 20
The two integers can be -21 and -20, OR 20 and 21.
Answer:
The answer is three
Step-by-step explanation:
Answer:
(14-9i)+(2+3i) = 16-6i
Step-by-step explanation:
We need to find the equivalent of (14-9i)+(2+3i).
We need to add the two expressions.
(14-9i)+(2+3i) = 14+2 -9i+3i
= 16-6i
Here, the real part is 16
The imaginary part is -6
Hence, the required answer is equal to 16-6i.
Answer:
118 i think
Step-by-step explanation:
-2{-7-2[3 squared + 2 to the power of 4]-8÷4}
-2{-7-2{9+16]-2}
-2{-7-50-2}
-2(-59)
118
MP = P - M = (0, 5) - (5, 6) = (0-5, 5-6) = (-5, -1) |MP| = √((-5)^2 + (-1)^2) = √(25+1) = √26
