Imagine you have 50,000 atoms of uranium-238. If U-238 has a half-life of 4.5 billion years, how many U-238 atoms will be left a
2 answers:
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Answer: P= 1.64 atm
Explanation: solution attached.
Use Ideal gas law
PV= nRT
Derive for P
P= nRT/V R= 0.08205 L.atm/mol.K
Substitute the values.
Answer : The name of ionic compound is, Copper(II) fluoride.
Explanation :
Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.
Ionic compound are usually formed when a metal reacts with a non-metal.
The nomenclature of ionic compounds is given by:
1. Positive ion is written first.
2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.
is an ionic compound because copper element is a metal and fluorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The oxidation state of copper in is, (+2)
Thus, the name of ionic compound is, Copper(II) fluoride.
Answer:
The isotope notation for an ion of silver-109 with a charge of positive 1 is .
Explanation:
The elements with same atomic number with different mass numbers are called isotopes.
The isotopes of silver is as follows.
From the above two isotopes have same atomic number and different mass number.
From the given,the isotope notation for an ion of silver-109 with a charge of positive 1
It can be represented is as follows.
General representation of isotope is as in attachment.
