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tatyana61 [14]
2 years ago
14

Imagine you have 50,000 atoms of uranium-238. If U-238 has a half-life of 4.5 billion years, how many U-238 atoms will be left a

fter 4.5 billion years
Chemistry
2 answers:
Lelechka [254]2 years ago
8 0

Answer:25,000

Explanation:

I took the test

Mrac [35]2 years ago
8 0

25000 molecules of U-238 element will be left after 4.5 billion years.

<h2>What is half life of radioactive element?</h2>

<h3>Half life of radioactive element</h3>

Half-life of radioactive elements refers to the time interval needed for one-half of the atomic nuclei of a radioactive sample to decay. The change occurs in the radioactive element into other nuclear species by emitting particles and energy.

Radioactive decay reduces the number of radioactive nuclei up to half of its original value or molecules so we can conclude that 25000 molecules of U-238 element will be left after 4.5 billion years.

Learn more about radioactive here: brainly.com/question/1236735

Learn more: brainly.com/question/26182507

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Compare the mass of a proton to the mass of an electron.
Y_Kistochka [10]

Electrons are only about 0.054% as massive as neutrons and protons are only 99.86% as massive as the neutrons. The mass of the Proton is 1.67 x 10^-27 kg and the mass of the electron is 9.11 x 10^-31 kg. The mass of the electron is so much lighter than the mass of the proton.

5 0
3 years ago
The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c
netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is 4.58\times 10^{-3}M

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of oxygen gas

C_2\text{ and }p_2 are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used:  1 atm = 760 torr

C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm

Putting values in above equation, we get:

\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M

Hence, the solubility of oxygen gas at 628 torr is 4.58\times 10^{-3}M

4 0
3 years ago
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Lelechka [254]

Answer:

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Explanation: hope this helps

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Law of multiple proportions or Dalton's Law said that the ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers. 
In this example ratios are whole numbers, A:Z = 2.5 : 1 and A:Z = 2.2 : 1 are not whole number ratios.</span>

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