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tatyana61 [14]
2 years ago
14

Imagine you have 50,000 atoms of uranium-238. If U-238 has a half-life of 4.5 billion years, how many U-238 atoms will be left a

fter 4.5 billion years
Chemistry
2 answers:
Lelechka [254]2 years ago
8 0

Answer:25,000

Explanation:

I took the test

Mrac [35]2 years ago
8 0

25000 molecules of U-238 element will be left after 4.5 billion years.

<h2>What is half life of radioactive element?</h2>

<h3>Half life of radioactive element</h3>

Half-life of radioactive elements refers to the time interval needed for one-half of the atomic nuclei of a radioactive sample to decay. The change occurs in the radioactive element into other nuclear species by emitting particles and energy.

Radioactive decay reduces the number of radioactive nuclei up to half of its original value or molecules so we can conclude that 25000 molecules of U-238 element will be left after 4.5 billion years.

Learn more about radioactive here: brainly.com/question/1236735

Learn more: brainly.com/question/26182507

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A cart is rolling across the floor at a constant velocity of 2 m/s to the right. The cart is pushed again to the right, and it s
galben [10]

Answer: the answer is c.The unbalanced push causes the cart to speed up.

Explanation:

The application of an unbalanced force (the push) causes the cart to speed up. When the cart is in constant motion, the forces are balanced and there is no speeding up. Once an unbalanced force is added, the cart's speed changes.

6 0
3 years ago
Read 2 more answers
1.86 g H2 is allowed to react with 9.75 g N2 , producing 2.87g NH3.
svet-max [94.6K]

Answer:

                     (a)  Theoretical Yield  =  10.50 g

                      (b)   %age yield  = 27.33 %

Explanation:

Answer-Part-(a)

                 The balance chemical equation for the synthesis of Ammonia is as follow;

                                          N₂ + 3 H₂ → 2 NH₃

Step 1: Calculating moles of N₂ as;

                   Moles = Mass / M/Mass

                   Moles = 9.75 g / 28.01 g/mol

                   Moles = 0.348 moles of N₂

Step 2: Calculating moles of H₂ as;

                   Moles = Mass / M/Mass

                   Moles = 1.86 g / 2.01 g/mol

                   Moles = 0.925 moles

Step 3: Finding Limiting reagent as;

According to equation,

                1 mole of N₂ reacts with  =  3 moles of H₂

So,

             0.348 moles of N₂ will react with  =  X moles of H₂

Solving for X,

                     X = 3 mol × 0.348 mol / 1 mol

                     X = 1.044 mol of H₂

It shows that to consume 0.348 moles of N₂ completely we require 1.044 mol of Hydrogen while, as given in statement we are only provided with 0.925 moles of H₂ hence, hydrogen  is limiting reagent. Therefore, H₂ will control the final yield.

Step 4: Calculating moles of Ammonia as,

According to equation,

                3 mole of H₂ produces  =  2 moles of NH₃

So,

             0.925 moles of H₂ will produce  =  X moles of NH₃

Solving for X,

                     X = 2 mol × 0.925 mol / 3 mol

                     X = 0.616 mol of NH₃

Step 5: Calculating theoretical yield of Ammonia as,

                     Theoretical Yield  =  Moles × M.Mass

                     Theoretical Yield  =  0.616 mol  × 17.03 g/mol

                     Theoretical Yield  =  10.50 g

Answer-Part-(b)

                    %age yield  = Actual Yield / Theoretical Yield × 100

                    %age yield  = 2.87 g / 10.50 g × 100

                    %age yield  = 27.33 %

4 0
3 years ago
A student is building an electrical circuit. Which material should she choose for wires, and why.
r-ruslan [8.4K]

D. A metal such as copper, because its atom have very mobile electrons         - A-p-e-x verified!

<u>Have a Great Day!</u>

3 0
3 years ago
Draw the structure(s) of the major organic product(s) of the following reaction. 1. lithium diisopropylamide / hexane 2. 1 eq. C
Jobisdone [24]

Answer:

See explanation below

Explanation:

You are not providing the starting material, however, I manage to find a similar question to this, so I'm gonna use it as a basis to help you answer yours.

Now let's analyze what is happening in the reaction so we can predict the final product.

We have a ketone here, reacting at first with LDA. This is a very strong base that is commonly used in reactions with ketones and aldehydes to promove a condensation. To do this, as LDA is a strong base it will occur firts an acid base reaction, substracting the most acidic hydrogen in the molecule (Which in this case, is the Beta hydrogen of the carbonile). This will cause an enolate formation.

Then, this enolate will react with the CH3I and form a new product. The final result would be a ketone with a methyl group now attached. In the picture 2, you have the mechanism and final product.

Hope this helps

6 0
3 years ago
What is Alkali metals
seropon [69]

Answer:

The alkali metals consist of the chemical elements lithium, sodium, potassium, rubidium, caesium, and francium. Together with hydrogen, they constitute group 1, which lies in the s-block of the periodic table

The alkali metals are all shiny, soft, highly reactive metals at standard temperature and pressure and readily lose their outermost electron to form cations with charge +1.

3 0
3 years ago
Read 2 more answers
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