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tatyana61 [14]
2 years ago
14

Imagine you have 50,000 atoms of uranium-238. If U-238 has a half-life of 4.5 billion years, how many U-238 atoms will be left a

fter 4.5 billion years
Chemistry
2 answers:
Lelechka [254]2 years ago
8 0

Answer:25,000

Explanation:

I took the test

Mrac [35]2 years ago
8 0

25000 molecules of U-238 element will be left after 4.5 billion years.

<h2>What is half life of radioactive element?</h2>

<h3>Half life of radioactive element</h3>

Half-life of radioactive elements refers to the time interval needed for one-half of the atomic nuclei of a radioactive sample to decay. The change occurs in the radioactive element into other nuclear species by emitting particles and energy.

Radioactive decay reduces the number of radioactive nuclei up to half of its original value or molecules so we can conclude that 25000 molecules of U-238 element will be left after 4.5 billion years.

Learn more about radioactive here: brainly.com/question/1236735

Learn more: brainly.com/question/26182507

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Calculate the percent by mass of 4.35g of Na I dissolved in 105g of water​
Ludmilka [50]

<u>We are given:</u>

Mass of Na added = 4.35 grams

Mass of water = 105 grams

<u>Mass Percent of Na:</u>

Total mass of the solution = mass of solute + mass of solvent

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Mass percent of solute = (mass of solute / mass of solution) * 100

Mass percent of Solute = (4.35 / 109.35) * 100

Mass percent = 3.978 %

4 0
2 years ago
If 3.1 moles of potassium chloride react with oxygen, how many moles of potassium chlorate would be produced?
Likurg_2 [28]

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3 years ago
Select the keyword or phrase that will best complete each sentence.
pishuonlain [190]

Answer:

1) acetylide

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3) aldehydes

4) tautomers

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7) Keto

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Explanation:

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Oxomercuration of alkynes and hydroboration of alkynes are similar reactions in that they both yield carbonyl compounds that often exhibit keto-enol tautomerism.

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3 years ago
The volume of air in a person’s lungs is 615 mL at a pressure of 760. mmHg. Inhalation occurs as the pressure in the lungs drops
chubhunter [2.5K]

<u>Answer:</u> The final volume of lungs is 621.5 mL

<u>Explanation:</u>

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

The equation given by this law is:

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P_2\text{ and }V_2 are final pressure and volume.

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Putting values in above equation, we get:

760mmHg\times 615mL=752mmHg\times V_2\\\\V_2=\frac{760\times 615}{752}=621.5mL

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