I LITERALLY forgot this.it's nonlinears and linear..

Mathematics

2 answers:

poizon [28]3 years ago

8 0

$1^{st} \ line: \begin{cases} x = -2, \\ y = 5 \cdot (-2) +1 = -9. \end{cases} \newline

2^{nd} \ line: \begin{cases} x = -1, \\ y = 5 \cdot (-1) +1 = -4. \end{cases} \newline

3^{rd} \ line: \begin{cases} x = 0, \\ y = 5 \cdot 0 + 1 = 1. \end{cases} \newline

4^{th} \ line: \begin{cases} x = 1, \\ y = 5 \cdot 1 + 1 = 6. \end{cases} \newline

5^{th} \ line: \begin{cases} x = 2, \\ y = 5 \cdot 2 + 1 = 11. \end{cases}$

stellarik [79]3 years ago

7 0

X side
-2
-1
0
1
2

y side
-9
-4
1
6
11

I would say it would be nonlinear

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When Θ = 5 pi over 6, what are the reference angle and the sign values for sine, cosine, and tangent? Θ' = negative pi over 6; s

timama [110]

Answer:

Option C is correct.

Step-by-step explanation:

$\theta=\frac{5\pi }{6}$

We need to find reference angle and signs of sinФ, cosФ and tanФ

We know that $\theta=\frac{5\pi }{6}radians$ is equal to 150°

and 150° is in 2nd quadrant.

So, Ф is in 2nd quadrant.

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WORTH ALL MY POINTS PLEASE HELP

kari74 [83]

9514 1404 393

Answer:

(a) = 7 +3·5

Step-by-step explanation:

The given expression evaluates to ...

6 +2^4 = 6 +16 = 22

The offered choices evaluate to ...

7 +3·5 = 7 +15 = 22