Ethylene is a hydrocarbon which has the formula C ₂H ₄ or H₂C=CH₂. It is a colourless flammable gas with a faint "sweet and musky" odour when pure. It is the simplest alkene.
Ethylene is widely used in the chemical industry, and its worldwide production exceeds that of any other organic compound.
<h3>What is ethylene used for?</h3>
Medical: Ethylene is used as an anaesthetic. Metal Fabrication: Ethylene is used as oxy-fuel gas in metal cutting, welding and high velocity thermal spraying. Refining: Ethylene is used as refrigerant, especially in LNG liquefaction plants. Rubber & Plastics: Ethylene is used in the extraction of rubber.
<h3>Is ethylene harmful to humans?</h3>
* Ethylene gas can affect you when breathed in. * Skin contact with liquid Ethylene can cause frostbite. * Exposure to Ethylene can cause headache, dizziness, fatigue, lightheadedness, confusion and unconsciousness. * Ethylene is a HIGHLY FLAMMABLE and REACTIVE chemical and a DANGEROUS FIRE and EXPLOSION HAZARD.
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Answer is: mass <span>of 4,30 moles of sodium</span> is 98800 mg.
n(Na) = 4,30 mol.
m(Na) = ?
m(Na) = n(Na) · M(Na).
m(Na) = 4,30 mol · 23 g/mol.
m(Na) = 98,90 g.
m(Na) = 98,90 g · 1000 mg/1g.
m(Na) = 98900 mg.
n - amount of substance.
m - mass of substance.
M - molar mass of substance.
Landslides and slumps are forms of mass movements. Types of erosion both move, in different ways. In slumps, land breaks off in one piece, or chunk. Landslides are when rocks and dirt rapidly move down a slide.
3.124mg of I-131 is present after 32.4 days.
The 131 I isotope emits radiation and particles and has an 8-day half-life. Orally administered, it concentrates in the thyroid, where the thyroid gland is destroyed by the particles.
What is Half life?
The time required for half of something to undergo a process: such as. a : the time required for half of the atoms of a radioactive substance to become disintegrated.
Half of the iodine-131 will still be present after 8.1 days.
The amount of iodine-131 will again be halved after 8.1 additional days, for a total of 8.1+8.1=16.2 days, reaching (1/2)(1/2)=1/4 of the initial amount.
The quantity of iodine-131 will again be halved after 8.1 more days, for a total of 16.2+8.1+8.1=32.4 days, to (1/4)(1/2)(1/2)=1/16 of the initial quantity.
If the original dose of iodine-131 was 50mg, the residual dose will be (50mg)*(1/16)=3.124mg after 32.4 days.
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