The volume of the granite as determined by water displacement is 9.35 mL. This value in cm³ is 9.35cm³.
<h3>How to calculate volume in cm³?</h3>
The conversion factor of mL and cm³ is given as follows: 1 mL = 1 cm³
According to this question, the volume of the granite as determined by water displacement is 9.35 mL.
This value in cm³ can be converted as follows:
9.35mL × 1 = 9.35cm³
Therefore, the volume of the granite as determined by water displacement is 9.35 mL. This value in cm³ is 9.35cm³.
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Answer:
What are the choices? I would say if "Southern Hemisphere is winter" pick that one
Explanation:
Opposite sides of Earth
A. The mass of one mole of the virus is calculated by multiplying the mass of a single virus by the Avogadro's number which is equal to 6.022 x 10^23. Performing this operation,
mass = (9.0 x 10^-12 mg)(6.022 x 10^23) = 5.42 x 10^12 mg
In correct number of significant figures, the answer would only have to be 5.4 x 10^12 mg.
b. The number of moles of the virus that will have the same mass as the oil tanker is calculated by dividing the mass of the oil tanker by the mass of one mole of the virus. Note that doing division, both would have to have the same units.
n = (3.0 x 10^7 kg) / (5.4 x 10^12 mg)(1 g/1000 mg)(1 kg/1000 g)
Simplifying,
n = 6
In correct number of significant figures, the answer is 6.0.
Answer:
See Explanation
Explanation:
a. pH of 1M HOAc(aq)
HOAc ⇄ H⁺ + OAcˉ
C(eq) 1.0M x x
Ka = [H⁺][OAc⁻]/[HOAc] = x²/1.0M = 1.85x10⁻⁵
=> x = [H⁺] = SqrRt([HOAc]Ka) = SqrRt[(1M)(1.85x10ˉ⁵)] = 4.30x10ˉ³M
=> pH = -log[H⁺] = -log(4.30x10ˉ³) = 2.37
b. pH of 0.10M CH₃NH₃OH(aq)
CH₃NH₃OH => CH₃NH₃⁺ + OHˉ; Kb = 4.4x10ˉ⁴
C(eq) 0.10M x x
=> Kb = [CH₃NH₃⁺][OH⁻]/[CH₃NH₃] = x²/0.10M
=> x = [OHˉ] = SqrRt([CH₃NH₃OH]Kb) = SqrRt[(0.10M)(4.4x10ˉ⁴)] = 6.63x10ˉ³M
=> pOH = -log[OHˉ] = -log(6.63x10⁻³) = 2.18
=> pH = 14 – pOH = 14 – 2.18 = 11.82
c. pH of 0.30M HOAc/0.10M OAcˉ(aq)
HOAc ⇄ H⁺ + OAcˉ
C(eq) 0.30M x 0.10M
=> Ka = [H⁺][OAcˉ]/[HOAc] => [H⁺] = Ka[HOAc]/[OAcˉ]
= 1.85X10ˉ⁵(0.30M)/(0.10M) = 5.55X10ˉ⁵M
=> pH = -log[H⁺] = -log(5.55x10ˉ⁵) = 4.26
Cd + 2HCl → CdCl₂ + H₂, 2ZnS + 3O₂ → 2ZnO + 2SO₂ and CH₄ + 2O₂ → CO₂ + 2H₂O reactions are redox reaction.
<h3>What is redox reaction?</h3>
Redox reactions are those reactions in which oxidation and reduction process takes place simultaneously.
Above balanced equation is a redox reaction as in this reaction oxidation of Cadmium takes place from 0 to+2 state and reduction of hydrogen takes place from +1 to 0 state.
- CuCl₂ + Na₂S → 2NaCl + CuS
- CaCO₃ → CaO + CO₂
Above two balanced reaction are not the redox reaction as their is no oxidation or reduction takes place.
Above balanced equation is a redox reaction as in this reaction oxidation of sulfur takes place from -2 to+4 state and reduction of oxygen takes place from 0 to -2 state.
Above balanced equation is a redox reaction as in this reaction oxidation of carbon takes place from -4 to+4 state and reduction of oxygen takes place from 0 to -2 state.
Hence, Cd + 2HCl → CdCl₂ + H₂, 2ZnS + 3O₂ → 2ZnO + 2SO₂ and CH₄ + 2O₂ → CO₂ + 2H₂O reactions are redox reaction
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