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3 years ago

Please help asap loll

Chemistry

1 answer:

BlackZzzverrR [31]3 years ago

5 0

Explanation:

Metals -

Left side of periodic table
Malleable
Ductile
Good conductor
Mostly solid
Shinly lusture

Non-metals -

Poor conductor
Dull
Brittle
Right side of periodic table

Metalloids -

Properties of metals and non-metals.
Found on the 'staircase' of the periodic table.

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Refined, white table sugar is sucrose that has been "recrystallized." using methods you used in this experiment, describe how yo

kati45 [8]

<span>First, obtain an ample amount of water, two clean containers, a stirring rod and a porous material for filtering. Next, place the water in the first container and heat the water until it boils. Then add the crude sugar to the boiling water and remove the mixture from heat. While still hot, pour the mixture through the filter into the second container, to remove sediments. Allow the filtered mixture to cool, and sugar crystals will form in the container. The recrystallization will occur more quickly if you add a seeding agent, like a small amount of refined sugar, to the cool mixture, but it is not necessary.</span>

3 0

4 years ago

a 125 g chunk of aluminum at 182 degrees Celsius was added to a bucket filled with 365 g of water at 22.0 degrees Celsius. Ignor

Diano4ka-milaya [45]

<h3>Answer:</h3>

32.98°C

<h3>Explanation:</h3>

We are given the following;

Mass of Aluminium as 125 g

Initial temperature of Aluminium as 182°C

Mass of water as 265 g

Initial temperature of water as 22°C

We are required to calculate the final temperature of the two compounds;

First, we need to know the specific heat capacity of each;

Specific heat capacity of Aluminium is 0.9 J/g°C

Specific heat capacity of water is 4.184 J/g°C

<h3>Step 1: Calculate the Quantity of heat gained by water.</h3>

Assuming the final temperature is X°C

we know, Q = mcΔT

Change in temperature, ΔT = (X-22)°C

therefore;

Q = 365 g × 4.184 J/g°C × (X-22)°C

= (1527.16X-33,597.52) Joules

<h3>Step 2: Calculate the quantity of heat released by Aluminium </h3>

Using the final temperature, X°C

Change in temperature, ΔT = -(X°- 182°)C (negative because heat was lost)

Therefore;

Q = 125 g × 0.90 J/g°C × (182°-X°)C

= (20,475- 112.5X) Joules

<h3>Step 3: Calculating the final temperature</h3>

We need to know that the heat released by aluminium is equal to heat absorbed by water.

Therefore;

(20,475- 112.5X) Joules = (1527.16X-33,597.52) Joules

Combining the like terms;

1639.66X = 54072.52

X = 32.978°C

= 32.98°C

Therefore, the final temperature of the two compounds will be 32.98°C

7 0

4 years ago

A titration is carried out to determine the concentration of the acid in an old bottle of aqueous HCl whose label has become unr

egoroff_w [7]

Answer:

The concentration of HCl is - 0.2675 M

Explanation:

At equivalence point ,

Moles of $HCl$ = Moles of NaOH

Considering :-

$Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}$

Given that:

$Molarity_{NaOH}=0.250\ M$

$Volume_{NaOH}=32.1\ mL$

$Volume_{HCl}=30.0\ mL$

$Molarity_{HCl}=?\ M$

So,

$Molarity_{HCl}\times Volume_{HCl}=Molarity_{NaOH}\times Volume_{NaOH}$

$Molarity_{HCl}\times 30.0=0.250\times 32.1$

$Molarity_{HCl}=\frac{0.250\times 32.1}{30.0}=0.2675\ M$

<u>The concentration of HCl is - 0.2675 M</u>

4 0

3 years ago

Draw the structural formula for both of these alcohols:

Inga [223]

Answer:

Check the image above

explanation:

When naming organic compounds based on IUPAC; we take note of functional group, position of functional group.

In 2,3,4-trimethyl-3-heptanol, the functional group is hydroxyl group ( OH ). It is on position 3 (2,3,4-trimethyl<u>-</u><u>3</u><u>-</u>heptanol. Then we put it on the third carbon. Another functional group is methyl group, with three positions, 2, 3, and 4.

In 4-ethyl-4-octanol, the functional group is hydroxyl group ( OH ) which is in position 4 on the fourth carbon. Another functional group is ethyl group in position 4 on the fourth carbon. In this case, the functional groups that have same position, are put on that same carbon.

6 0

3 years ago

What is the mass, in grams, of 0.250 mol K2CO3?

svp [43]

Answer:

jug

Explanation:

4 0

3 years ago

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