The energy stored by a system of capacitors is given by

where Ceq is the equivalent capacitance of the system, and V is the voltage applied.
In the formula, we can see there is a direct proportionality between U and C. This means that if we want to increase the energy stored by 4 times, we have to increase C by 4 times, if we keep the same voltage.
Calling

the capacitance of the original capacitor, we can solve the problem by asking that, adding a new capacitor with

, the new equivalent capacitance of the system

must be equal to

. If we add the new capacitance X in parallel, the equivalent capacitance of the new system is the sum of the two capacitance

and since Ceq must be equal to 4 C1, we can write

from which we find
The east bound train travels at a speed of 95 mile per hour and the west bound train at 75 miles per hour.
Assuming eastbound train will cover distance x then the west bound train will cover distance 272-x .
Therefore, since time taken will be the same then; x/95 = (272-x)/75
= 75x = 95 (272-x)
= 75x = 25840 - 95x
= 170 x= 25840
x = 152 miles
Thus time taken will either be x/95 or (272-x)/75
= 152/95
= 1.6 hours or 1 hour 36 minutes
Answer: The answer is B
Explanation:
Work can be defined as the energy that is required to apply a force to an object in order to move it from one point to another. In physics, work = force x distance travelled. On the other hand, Power is the work done per time. In other words, it the rate at which work is done and is determined by using the formula, Power = Work/time. In these relationships, it can be seen that power is directly proportional to the amount of work done, hence as power increases, more work is done.
Answer:
Explanation:
Given
frequency of wave 
We know velocity is given by

where
=wavelength



Answer:
ФB = 4.89 W
Explanation:
In order to calculate the magnetic flux trough the triangular wire loop, you use the following formula:
(1)
B: magnitude of the magnetic field = 4.15T
A: area of the triangular loop
θ: angle between the normal to the surface and the direction of the magnetic field = 0°
Both direction of the magnetic field and the normal vector to the surface are parallel.
You calculate the area of the triangular loop:
(2)
b: base = 1.65 m
h: height = 

Next, you replace the values of A and B in the equation (1):

The magnetic flux trough the triangular wire loop is 4.89W