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3 years ago

Multiply 0.00032 cm by 4.02 cm and express the answer in scientific notation

Physics

2 answers:

FromTheMoon [43]3 years ago

4 0

0.00032cm*4.02=1.2864 × 10^-3 in scientific notation.

nignag [31]3 years ago

3 0

Answer

$1.2864*10^{-3} cm^{2}$

Explanation:

First we multiply as normal:

0.00032 cm * 4.02 cm = 0.0012864 cm²

It is important to multiply the units too which is why centimeters become square centimeters.

Then we write the answer in scientific notation:

$0.0012864 cm^{2} = 1.2864*10^{-3} cm^{2}$

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timurjin [86]

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<h3>What is the work of Harlow Shapley?</h3>

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2 years ago

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olganol [36]

Answer:

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Explanation:

8 0

2 years ago

A net force of 3000 N is accelerating a 1200 kg elevator upward. If the elevator starts from rest, how long will it take to trav

alexdok [17]

F = net force acting on the elevator in upward direction = 3000 N

m = mass of the elevator = 1200 kg

a = acceleration of the elevator = ?

Acceleration of the elevator is given as

a = F/m

a = 3000/1200

a = 2.5 m/s²

v₀ = initial velocity of the elevator = 0 m/s

Y = displacement of the elevator = 15 m

t = time taken

Using the kinematics equation

Y = v₀ t + (0.5) a t²

15 = (0) t + (0.5) (2.5) t²

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4 years ago

In February 2004, scientists at Purdue University used a highly sensitive technique to measure the mass of a vaccinia virus (the

OlgaM077 [116]

Answer:

a) m_v = m_s (( $\frac{w_o}{w}$ )² - 1) , b) m_v = 1.07 10⁻¹⁴ g

Explanation:

a) The angular velocity of a simple harmonic motion is

w² = k / m

where k is the spring constant and m is the mass of the oscillator

let's apply this expression to our case,

silicon only

w₉² = $\frac{K}{m_s}$

k = w₀² m_s

silicon with virus

w² = $\frac{k}{m_s + m_v}$

k = w² (m_v + m_s)

in the two expressions the constant k is the same and q as the one property of the silicon bar, let us equal

w₀² m_s = w² (m_v + m_s)

m_v = ( $\frac{w_o}{w}$ )² m_s - m_s

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4 0

3 years ago

A 40-cmcm-long tube has a 40-cmcm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. A

Licemer1 [7]

Answer:

1070 Hz

Explanation:

First, I should point out there might be a typo in the question or the question has inconsistent values. If the tube is 40 cm long, standing waves cannot be produced at 42.5 cm and 58.5 cm lengths. I assume the length is more than the value in the question then. Under this assumption, we proceed as below:

The insert in the tube creates a closed pipe with one end open and the other closed. For a closed pipe, the difference between successive resonances is a half wavelength $\frac{\lambda}{2}$ .