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3 years ago

B) Write the name of the deviceswhich are shown in the givenfigures and write their uses

Physics

1 answer:

Katena32 [7]3 years ago

3 0

Answer:

transparent Prism

Explanation:

The device shown is a prism. It is used to study the refraction of light according with its wavelength as it transverses from a medium (air for example) to another (either glass, fluorite, plastic), and vice versa.

For that reason is also used to separate white light into its spectral wavelength components.

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Any energy transformation involves the loss of some energy as

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Any energy transformation involves the loss of some energy as B. Heat.

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Michael tells Erica he weighs 104 pounds. Erica says she is 44 kilograms. If there are 2.2 pounds in a

Andrej [43]

Answer:

Michael is heavier.

Explanation:

If Michael is 104 pounds, that is equal to 47 kg.

Erica is 44 kg which is 97 pounds.

104 is greater than 97, and 47 is greater than 44.

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4 years ago

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g (12 points) The time between incoming phone calls at a call center is a random variable with exponential density p(x) = 1 r e

rusak2 [61]

Answer:

$(1)p(x)\geq 0\\(2)\int_{0}^{\infty} p(x) dx=0$

Explanation:

A function f(x) is a Probability Density Function if it satisfies the following conditions:

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Given the function:

$p(x)=\dfrac{1}{r}e^{-x/r} \: on\: [0,\infty), where\:r=\dfrac{20}{ln(2)}$

(1)p(x) is greater than zero since the range of exponents of the Euler's number will lie in $[0,\infty).$

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$\int_{0}^{\infty} p(x)=\int_{0}^{\infty} \dfrac{1}{r}e^{-x/r}\\=\dfrac{1}{r} \int_{0}^{\infty} e^{-x/r}\\=-\dfrac{r}{r}\left[e^{-x/r}\right]_{0}^{\infty}\\=-\left[e^{-\infty/r}-e^{-0/r}\right]\\=-e^{-\infty}+e^{-0}\\SInce \: e^{-\infty} \rightarrow 0\\e^{-0}=1\\\int_{0}^{\infty} p(x)=1$

The function p(x) satisfies the conditions for a probability density function.

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3 years ago

Which statements describe the motion of the object represented by the graph? Check all that apply.

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Answer:a, d, e

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A neutron consists of one "up" quark of charge +2e/3 and two "down" quarks each having charge -e/3. If we assume that the down q

Anon25 [30]

Answer:

The magnitude of the electrostatic force is 120.85 N

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We can use Coulomb's law to find the electrostatic force between the down quarks.

In scalar form, Coulomb's law states that for charges $q_1$ and $q_2$ separated by a distance d, the magnitude of the electrostatic force F between them is: