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Genrish500 [490]
3 years ago
6

B) Write the name of the deviceswhich are shown in the givenfigures and write their uses​

Physics
1 answer:
Katena32 [7]3 years ago
3 0

Answer:

transparent Prism

Explanation:

The device shown is a prism. It is used to study the refraction of light according with its wavelength as it transverses from a medium (air for example) to another (either glass, fluorite, plastic), and vice versa.

For that reason is also used to separate white light into its spectral wavelength components.

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Coral reefs reduce the amount of carbon dioxide in the oceans. People have destroyed many natural coral reefs through pollution.
Mariulka [41]

The Answer is A!

Hope this helps :)

7 0
4 years ago
List five objects in your daily life that produce sounds with a high pitch and five that produce sounds with a low pitch.
drek231 [11]

Answer:

Explanation:

High pitch:

-birds chirping

-nails on a chalkboard

-flies buzzing

-children squealing

-whistle

Low pitch:

-thunder

-dogs barking

- earthquakes

-  bass drum,

-cannon shot,

8 0
3 years ago
Distinguish the steps in the process of stopping a tractor, keeping them in proper order.
weeeeeb [17]
Ahhh, there aren’t option to work with :v
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7 0
3 years ago
Read 2 more answers
Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia
Sedaia [141]

Answer:

a_2\ =\ -33.65\ m/s^2

Explanation:

Given,

For the first rocket,

  • Initial velocity of the first rocket A = u_1\ =\ 4600\ m/s.
  • Acceleration of the first rocket = a_1\ =\ -18\ m/s^2

For the second rocket,

  • Initial velocity of the second rocket B = u_2\ =\ 8200 m/s.
  • Displacement of both the rockets A and B = s = 0 m

Fro the first rocket,

Let 't' be the time taken by the first rocket A for whole the displacement

\therefore s\ =\ u_1t\ +\ \dfrac{1}{2}a_1t^2\\\Rightarrow 0\ =\ 4600t\ -\ 0.5\times 18t^2\\\Rightarrow t\ =\ \dfrac{4600}{0.5\times 18}\\\Rightarrow t\ =\ 511.11 sec

Let a_2 be the acceleration of the second rocket B for the same time interval

from the kinematics,

\therefore s\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s\ =\ u_2t\ +\ \dfrac{1}{2}a_2t^2\\\Rightarrow a_2\ =\ \dfrac{2s\ -\ 2u_2t}{t^2}\\\Rightarrow a_2\ =\ \dfrac{0\ -\ 2u_2t}{t^2}\\

\Rightarrow a_2\ =\ -\dfrac{2u_2}{t}\\\Rightarrow a_2\ =\ -\dfrac{2\times 8600}{511.11}\\\Rightarrow a_2\ =\ -33.65\ m/s^2

Hence the acceleration of the second rocket B is -33.65\ m/s^2.

6 0
3 years ago
A 2.4-kg cart is rolling along a frictionless, horizontal track towards a 1.7-kg cart that is held initially at rest. The carts
inessss [21]

Answer:

Explanation:

Mass of first cart M1=2.4kg

Velocity of first cart U1=4.1m/s

Mass of second cart M2=1.7kg

Second cart is initially at rest U2=0

After an instant, the velocity of the second cart is U2=-2.8m/s

Now after collision the two cart move together with the same velocity I.e inelastic collision

Using conservation of momentum

Momentum before collision, = momentum after collision

M1U1 + M2U2 = (M1+M2)V

2.4×4.1 + 1.7× -2.8 =(2.4+1.7)V

9.84 - 4.76 = 4.1V

5.08=4.1V

V=5.08/4.1

V=1.24m/s

The momentum of the two cart at that instant is

M1U1+M2U2

2.4×4.1 + 1.7× -2.8

9.84 - 4.76

5.08kgm/s

So the momentum at the instant the velocity is 4.1m/s for cart 1 and -2.8m/s for cart 2 is 5.08kgm/s

3 0
3 years ago
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