All categories

2 years ago

Newton discovered that gravity behaves differently in space than it does on Earth. true or false?

1 answer:

5 0

Yes. It is true. Gravity behaves differently than on earth. In-fact, as we go above the earth surface the gravity decreases. Gravity as we go above the earth surface can be calculated using following formula:

g' = g(1-2h/R)

Hence, it is true that the gravity behaves differently than on earth.

You might be interested in

Use the SI prefixes in Table 3 of this chapter to convert these hypothetical units of measure into appropriate quantities: a. 10

8090 [49]

A. 10 rations = 1 deca-ration.

b. 2000 mockingbirds = 2 x 10³ = 2 kilo-mockingbirds.

c. 10⁻⁵ phones = 1 micro-phones.

d. 10⁻⁹ goats = 1 nano-goats.

e. 1018 miners = 1.018 x 10³ = 1.018 kilo-miners.

4 0

2 years ago

Electrically inert metal ball A is connected to the ground by a wire. What happens to the charge of this ball if you bring a neg

kaheart [24]

Explanation:

They will repel, meaning that they are made of an electrical conductor.

7 0

3 years ago

An 1100kg car reached 30m/s in 9s from rest. What force did the engine provide?

malfutka [58]

Answer:

≅3666.67 N

Explanation:

Use Newton's 2nd law, F = ma where F=force applied, m = mass of the object,

a = acceleration acquired by the object.

a= (v-u)/t where v = final velocity, u = initial velocity and t = time taken

calculate a = (30-0)/9 ≅ 3.33 m/s2

Then F = 1100×a = 3666.67 N

3 0

3 years ago

URGENTTT PLEASE HELPPPP. You put m1 = 1 kg of ice cooled to -20°C into mass m2 = 1 kg of water at 2°C. Both are in a thermally i

STatiana [176]

Answer:

Explanation:

heat lost by water will be used to increase the temperature of ice

heat gained by ice

= mass x specific heat x rise in temperature

1 x 2090 x t

heat lost by water in cooling to 0° C

= mcΔt where m is mass of water , s is specific heat of water and Δt is fall in temperature .

= 1 x 2 x 4186

8372

heat lost = heat gained

1 x 2090 x t = 8372

t = 4°C

There will be a rise of 4 degree in the temperature of ice.

5 0

2 years ago

) A striker can give the ball an initial speed of 30m/s. Within what two elevation angles must he kick

sveticcg [70]

Answer:

about 19.6° and 73.2°

Explanation:

The equation for ballistic motion in Cartesian coordinates for some launch angle α can be written ...

y = -4.9(x/s·sec(α))² +x·tan(α)

where s is the launch speed in meters per second.

We want y=2.44 for x=50, so this resolves to a quadratic equation in tan(α):

-13.6111·tan(α)² +50·tan(α) -16.0511 = 0

This has solutions ...

tan(α) = 0.355408 or 3.31806

The corresponding angles are ...

α = 19.5656° or 73.2282°

The elevation angle must lie between 19.6° and 73.2° for the ball to score a goal.

_____

I find it convenient to use a graphing calculator to find solutions for problems of this sort. In the attachment, we have used x as the angle in degrees, and written the function so that x-intercepts are the solutions.

5 0

2 years ago