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3 years ago

Newton discovered that gravity behaves differently in space than it does on Earth. true or false?

1 answer:

5 0

Yes. It is true. Gravity behaves differently than on earth. In-fact, as we go above the earth surface the gravity decreases. Gravity as we go above the earth surface can be calculated using following formula:

g' = g(1-2h/R)

Hence, it is true that the gravity behaves differently than on earth.

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an object moving at 10. km/hr has a kinetic energy of 10. J. what is the kinetic energy of the same object if it is moving at 20

Schach [20]

Kinetic energy is related to velocity by:
KE = (1/2)mv^2

solve for mass m
10 = (1/2)m(10)^2
10 = (1/2)m(100)
10= 50m
10/50 = m
1/5 = m

at 20 km/hr

KE = (1/2)(1/5)(20)^2
KE = (1/10)(400)
KE = 40 J

5 0

3 years ago

Will give brainliest to right answer!

viva [34]

The correct answer is D.

8 0

3 years ago

Four point charges have the same magnitude of 2.4×10^−12C and are fixed to the corners of a square that is 4.0 cm on a side. Thr

Gwar [14]

Answer:

7.2N/C

Explanation:

Pls see attached file

6 0

3 years ago

The SAF operates the M113 Ultra APC.

HACTEHA [7]

The volume of the object must be no larger than $11.15 m^3$ .

Explanation:

In order for an object to be able to float in water, its density must be equal or smaller than the water density.

The density of water is:

$\rho = 1000 kg/m^3$

This means that the density of the object must be no larger than this value.

We also know that the density of an object is given by

$\rho = \frac{m}{V}$

where

m is the mass of the object

V is its volume

For the object in this problem, the mass is

$m=1.115\cdot 10^4 kg$

Therefore, we can re-arrange the equation to find its volume:

$V=\frac{m}{\rho}=\frac{1.115\cdot 10^4}{1000}=11.15 m^3$

So, the volume of the object must be no larger than $11.15 m^3$ .

Learn more about density:

brainly.com/question/5055270

brainly.com/question/8441651

#LearnwithBrainly

8 0

3 years ago

What speed must an electron have if its momentum is to be the same as that of an x-ray photon with a wavelength of 0.30?

lorasvet [3.4K]

The momentum of the x-ray photon is p = h/lambda . Lambda is the wavelength (0.30nm=3x10^(-9)m) and h is Planck's constant,(h=6.62607004 × 10-34 m2 kg / s).The momentum is: 2.2 x 10^(-25).

The momentum can be calculated also as: p=mv, where m is the mass of the electron and v is the speed.

So v=p/m,p is known,and also the mass of the electron (m=9.10938356 × 10-31 kilograms).

v=2.2 x 10^(-25)/9.10938356 × 10-31 kilograms=0.24 x 10^6 m/s

8 0

3 years ago