Answer:
Se the explanation below
Explanation:
We do not feel these forces of these bodies, because they are very small compared to the force of Earth's attraction. Although its mass is greater than that of a human being, its mass is not compared to the Earth's mass. In order to understand this problem we will use numerical data and the universal gravitation formula, to give validity to the explanation.
<u>Force exerted by the Earth on a human being</u>
<u />
Where:
G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]
m1 = mass of the person = 80 [kg]
m2 = mass of the earth 5.97*10^24[kg]
r = distance from the center of the earth to the surface or earth radius = 6371 *10^3 [m]
<u />
Now replacing we have
![F = 6.673*10^{-11} *\frac{80*5.97*10^{24}}{(6371*10^{3})^{2} } \\F = 785[N]](https://tex.z-dn.net/?f=F%20%3D%206.673%2A10%5E%7B-11%7D%20%2A%5Cfrac%7B80%2A5.97%2A10%5E%7B24%7D%7D%7B%286371%2A10%5E%7B3%7D%29%5E%7B2%7D%20%20%7D%20%5C%5CF%20%3D%20785%5BN%5D)
<u>Force exerted by a building on a human being</u>
<u />
Where:
G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]
m1 = mass of the person = 80 [kg]
m2 = mass of the earth 300000 [ton] = 300 *10^6[kg]
r = distance from the building to the person = 2[m]
![F = 6.673*10^{-11}*\frac{80*300*10^6}{2^{2} } \\F= 0.4 [N]](https://tex.z-dn.net/?f=F%20%3D%206.673%2A10%5E%7B-11%7D%2A%5Cfrac%7B80%2A300%2A10%5E6%7D%7B2%5E%7B2%7D%20%7D%20%20%5C%5CF%3D%200.4%20%5BN%5D)
As we can see the force exerted by the Earth is 2000 times greater than that exerted by a building with the proposed data.
Answer:
Because when people under the age of 21 try to buy alcohol, they need to be verified by their state that they are that age. So if they are under legal age, 21, the store isn't allowed to give them the Alcoholic beverage.
Explanation:
By calculating the crests, you can find the waves' frequency.
Hope this helps!
Answer:
Time taken, 
Explanation:
It is given that, a small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal circle so that the thread’s trajectory describes a cone as shown in attached figure.
From the figure,
The sum of forces in y direction is :
Sum of forces in x direction,
.............(1)
Also, 
Equation (1) becomes :
...............(2)
Let t is the time taken for the ball to rotate once around the axis. It is given by :
Put the value of T from equation (2) to the above expression:
On solving above equation :
Hence, this is the required solution.
Answer:
Time period of the osculation will be 0.0671 sec
Explanation:
It is given a vertical spring is stretched by 4 cm
So change in length of the spring x = 4 cm = 0.04 m
Mass which is hung from it m = 12 gram = 0.012 kg
Sprig force will be equal to weight of the mass
So 
k = 244.7 N/m
Now new mass is m = 28 gram = 0.028 kg
So time period with new mass will be
