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Ne4ueva [31]
2 years ago
6

A line includes the points (3, 7) and (14, 18). What is its equation in slope-intercept form?

Mathematics
1 answer:
sukhopar [10]2 years ago
7 0

Answer:

y=x+4

Step-by-step explanation:

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The answer is B not mutually exclusive
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Find the sum 6 1/4 + 7 2/3
ki77a [65]

Answer:

13 11/12.

Step-by-step explanation:

First, we multiply 1/4 and 2/3 with it's least common denominator, 12. Now, we have 6 3/12 and 7 8/12. We now add this together to get the sum of 13 11/12.

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Help I am very bad at math I need answers by tomorrow if you can help please do​
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}-  Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A

2)  Sec² A - Tan² A = 1

LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A -  Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\

3) LHS  = Cosec² A + Cot² A

             = Cosec² A +  Cosec² A - 1

            = 2Cosec² A - 1   = RHS

4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\          = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1

3 0
3 years ago
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mote1985 [20]

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Step-by-step explanation:

Area of four walls = Curved surface area

                             = perimeter × height

                              =    28          ×   3.5

                              = 98 m square  

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1 year ago
More than half of the moon is visible from Earth; light appears to be increasing​
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Answer:

cool

Step-by-step explanation:

whats ur question about it?

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