Answer:
Where's the picture?
Step-by-step explanation:
Can't see it.
We get tne n-th term with: tn=1/3tn-1
We know that the first term is t1=81, so 81=1/3t*1-1
81=1/3t-1
82=1/3t
82*3t=1
3t=1/82
t=1/82*3=1/246
The second term is: 1/
2*(1/246)*2)-1
We get the third term by replacing n with 3 and so on...
Answer: Reformatting the input :
Changes made to your input should not affect the solution:
(1): "y3" was replaced by "y^3". 1 more similar replacement(s).
STEP
1
:
Equation at the end of step 1
(23x2 • y3) - 5
STEP
2
:
Trying to factor as a Difference of Cubes
2.1 Factoring: 8x2y3-5
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0+b3 =
a3+b3
Check : 8 is the cube of 2
Check : 5 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Final result :
8x2y3 - 5
Answer:
= 2n - 3
Step-by-step explanation:
Note the difference in consecutive terms is constant, that is
1 - (- 1) = 3 - 1 = 5 - 3 = 7 - 5 = 2
This indicates that the terms are an arithmetic sequence with
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 1 and d = 2, thus
= - 1 + 2(n - 1) = - 1 + 2n - 2 = 2n - 3
