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Westkost [7]
3 years ago
7

What is the force applied to a baseball that has a mass of 142kg and has a acceleration of 30m/s to the power of 2

Physics
1 answer:
aev [14]3 years ago
7 0
  • Mass=m=142kg
  • Acceleration=a=30m/s
  • Force=F

Using Newton's second law

\\ \sf\Rrightarrow F=ma

\\ \sf\Rrightarrow F=142(30)

\\ \sf\Rrightarrow F=4260N

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Answer:

Explanation:

F = m * a

The apple's acceleration is not influenced by the acceleration due to gravity for this question.  In real life it most certainly is influenced by gravity.

F = m * a

F = 10 Newtons.

a = 6 m/s^2

m = 10/6 = 1.66 kg. Mighty  large apple

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Determine the value of the force exerted by the surface (normal force) on a
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53.5 N

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What is pH? (NEED ANSWER ASAP)
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3 years ago
A 2.3 kg , 20-cm-diameter turntable rotates at 110 rpm on frictionless bearings. Two 460 g blocks fall from above, hit the turnt
boyakko [2]

Answer:

The correct solution is "64 RPM".

Explanation:

The given values are:

Mass,

M = 2.3 kg

Diameter,

D = 20 cm

i.e.,

   = 0.2 m

Rotates at,

N = 110 rpm

Mass of block,

m = 460 g

i.e.,

   = 0.46 kg

According to angular momentum's conservation,

⇒  I_1\omega_1=I_2\omega_2

then,

⇒  I_1=\frac{1}{2}MR_2

On substituting the values, we get

⇒      =\frac{1}{2}\times 2.3\times (0.1)^2

⇒      =\frac{1}{2}\times 0.023

⇒      =0.0115 \ kg \ m^2

Now,

⇒  I_2=I_1+2mR^2

        =0.0115+2\times 0.46\times (0.1)^2

        =0.0115+0.0092

        =0.02 \ kg \ m^2

then,

⇒  0.0115\times 110=0.02\omega_2

⇒              1.265=0.02\omega_2

⇒                  \omega_2=\frac{1.265}{0.02}

⇒                       =63.25 \ or \ 64 \ RPM

7 0
3 years ago
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