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ss7ja [257]
2 years ago
13

19. A 0.0340 kg bullet traveling at 120 m/s embeds itself in a 1.24 kg wooden block which

Physics
1 answer:
Blababa [14]2 years ago
3 0

Answer: x ≈ 36.3 cm

Explanation:

Conservation of momentum during the collision

0.0340(120) + 1.24(0) = (0.0340 + 1.24) v

v = 3.2025 m/s

The kinetic energy of the block/bullet mass will convert to spring potential

½kx² = ½mv²

x = √(mv²/k)

x = √(1.274(3.2025²) / 99.0)

x = 0.363293... ≈ 36.3 cm

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A 72.9-kg base runner begins his slide into second base when moving at a speed of 4.02 m/s. The coefficient of friction between
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Answer:

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Explanation:

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W = 1/2 × 72.9 kg(0 m²/s² - 16.1604 m²/s²)

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4 0
2 years ago
If a ball is thrown alt 96 m/s, and it travels 3 seconds, what is the total distance the ball travelec
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