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LUCKY_DIMON [66]
3 years ago
8

how to A golf ball of mass 0.045 kg is hit off the tee at a speed of 45 m/s. The golf club was in contact with the ball for 3.5

× 10−3 s. Find (a) the final momentum of the ball, (b) the impulse imparted to the golf ball, and (c) the average force exerted on the ball by the golf club.
Physics
2 answers:
Kruka [31]3 years ago
7 0

Answer:

a) Final Momentum = P2 =2.025 kgm/s

b) Impulse = J = 2.025 kgm/s

c) Favg = 578.57 N

Explanation:

Mass of the golf ball = m = 0.045 kg

Initial speed = V1 = 0 m/s  

Final Speed = V2 = 45 m/s  

Time = t = 3.5 × 10^-3

a) Final Momentum = P2 = mV2 = (0.045)(45) = 2.025 kgm/s

b) Impulse = J = change in momentum = ∆P = mV2 – mV1

                     J = (0.045)(45) – (0.045)(0) = 2.025 kgm/s

c) Impulse = Favg × t

   Favg = J/t = 2.025/3.5 × 10^-3

   Favg = 578.57 N                                                                                            

Alexandra [31]3 years ago
4 0

Answer: a) 12857.1 m/s/s b) 578.6 N

Explanation:

Impulse = change in momentum

Ft = mV2 - mV1

V = AT, 45 / .0035 = 12857.1 m/s/s

(b) .045 x 12857.1 = 578.6 N

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Answer:

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mixer [17]

The cylinder's electric field magnitude, at a distance <em>r</em> from the axis of the cylinder (greater than the cylinder's radius), is equal to E= \frac{\lambda}{2\pi \epsilon_0 \cdot r}

<h3>Further explanation</h3>

Matter is the building block of everything that we encounter in our lives. Matter is made of atoms, which are in turn made of tiny particles which are called electrons, protons, and neutrons. The ammount of these 3 elements, and their topological configuration in the atoms, is what determines what a certain element is (like Carbon, Hydrogen, Iron, etc).

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This charge causes the material to have an Electric field, which is a measure of how much does it attract or repel electrons. In the case of our problem, we need to compute exactly that, the Electric field. In our problem, we have an infinitely long cylinder with a linear charge density \lambda, this means that all parts of the cylinder have the same charge, and due to symmetry, the electric field is constant on the angular and longitudinal directions of the cylinder.

This makes easy to apply Gauss' Law, since for a Gaussian curve in the shape of a concentric cylinder (with a higher radius than that of our charged cylinder) we can write:

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E= \frac{\lambda}{2\pi \epsilon_0 \cdot r}

<h3 /><h3>Learn more</h3>
  • Description on Electric fields: brainly.com/question/8971780
  • Relation between electric fields and magnetism: brainly.com/question/2838625
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