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Sedbober [7]
2 years ago
10

A car traveling at 50 m/s uniformly accelerates to 60 m/s over an 58 second interval. What is the displacement?

Physics
2 answers:
BaLLatris [955]2 years ago
7 0
<h2>Answer:</h2>

The displacement of <u>3190 m</u> a car can travel if velocity is accelerated uniformly for 50 m⁄s to 60 m⁄s over a 58 second interval.

<h2>Explanation:</h2>

A car traveling at 50 m⁄s to 60 m⁄s over a 58 second interval the displacement of car is found by using the formula:

s=\frac{1}{2}(v+u) t

Where,  

v is final velocity = 60 m/s

u is initial velocity = 50 m/s

t is time taken = 58 s

s is displacement

Now,

\Rightarrow s=\frac{1}{2}(60+50) 58

\Rightarrow s=\frac{1}{2}(110) 58

\therefore s=3190 \ m

Hence, a car travels 3190 m if velocity is accelerated uniformly for 50 m⁄s to 60 m⁄s over a 58 second interval.

yawa3891 [41]2 years ago
6 0

Explanation:

here u = 50m/s

v = 60m/s

t = 58 s

then a = (60-50)/58 m/s2

= 0.17m/s2

now s= ut+1/2at2

so , 50×58+0.5×0.17×(58)^2 m

= 3185.94 m

= 3.18 km

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Which of the following are early clues that signal an earthquake may occur? Select all that apply. Changes in magnetic propertie
enot [183]

The following answers apply;

  • Changes in magnetic properties of rock
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These other choices may be good indicators of an imminent volcanic eruption;

Movement of magma

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6 0
3 years ago
Read 2 more answers
Over a 24-hour period, the tide in a harbor can be modeled by one period of a sinusoidal function. the tide measures 5.15 ft at
RSB [31]
<span>f(x) = 5.05*sin(x*pi/12) + 5.15

   First, you need to determine the period of the function. The period will be the time interval between identical points on the sinusoidal function. For this problem, the tide is rising and at 5.15 at midnight for two consecutive days. So the period is 24 hours. Over that 24 hour period, we want the parameter passed to sine to range from 0 to 2*pi. So the scale factor for x will be 2*pi/24 = pi/12 which is approximately 0.261799388. The next thing to note is the magnitude of the wave. That will simply be the difference between the maximum and minimum values. So 10.2 ft - 0.1 ft = 10.1 ft. And since the value of sine ranges from -1 to 1, we need to divide that magnitude by 2, so 10.1 ft / 2 = 5.05 ft.

   So our function at this point looks like f(x) = 5.05*sin(x*pi/12) But the above function ranges in value from -5.05 to 5.05. So we need to add a bias to it in order to make the low value equal to 0.1. So 0.1 = X - 5.05, 0.1 + 5.05 = X, 5.15 = X. So our function now looks like:
  f(x) = 5.05*sin(x*pi/12) + 5.15

   The final thing that might have been needed would have been a phase correction. With this problem, we don't need a phase correction since at X = 0 (midnight), the value of X*pi/12 = 0, and the sine of 0 is 0, so the value of the equation is 5.15 which matches the given value of 5.15. But if the problem had been slightly different and the height of the tide at midnight has been something like 7 feet, then we would have had to calculate a phase shift value for the function and add that constant to the parameter being passed into sine, making the function look like:
 f(x) = 5.05*sin(x*pi/12 + C) + 5.15
  where
 C = Phase correction offset.

   But we don't need it for this problem, so the answer is:
 f(x) = 5.05*sin(x*pi/12) + 5.15

   Note: The above solution assumes that angles are being measured in radians. If you're using degrees, then instead of multiplying x by 2*pi/24 = pi/12, you need to multiply by 360/24 = 15 instead, giving f(x) = 5.05*sin(x*15) + 5.15</span>
7 0
3 years ago
Any body moving with simple harmonic motion is being acted on by a force that is:__________.
Stella [2.4K]

Answer:

B

Explanation:

Because this oscillations occur when the restoring force is directly proportional to displacement, given as

F=-kx

Where k= force constant

X= displacement

6 0
3 years ago
You want to move a 4- kg bookcase to a different place in the living room. If u push with a force of 65 n and the bookcase accel
IrinaK [193]

Answer:

1.65

Explanation:

The equation of the forces along the horizontal direction is:

F-F_f = ma (1)

where

F = 65 N is the force applied with the push

F_f is the frictional force

m = 4 kg is the mass

a=0.12 m/s^2 is the acceleration

The force of friction can be written as F_f = \mu R (2), where

\mu is the coefficient of kinetic friction

R is the normal force exerted by the floor

The equation of forces along the vertical direction is

R-mg=0 (3)

since the bookcase is in equilibrium. Substituting (2) and (3) into (1), we find

F-\mu mg = ma

And solving for \mu,

\mu = \frac{F-ma}{mg}=\frac{65-(4)(0.12)}{4(9.8)}=1.65

7 0
2 years ago
2. Unless an object at rest is acted upon by a force, it stays at rest due to it's __________.
Leokris [45]

Inertia. (Newton's Laws of Motion)

5 0
3 years ago
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