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xxTIMURxx [149]
2 years ago
10

How long will it take a ball to hit the ground if it's dropped from a height of 2.0 m?

Physics
1 answer:
love history [14]2 years ago
8 0

Answer:

0.63 s

Explanation:

We have,

  • Height, h = 2.0 m
  • Initial velocity, u = 0 m/s
  • Acceleration due to gravity, g = 10 m/s²

We have to find the time taken.

⠀⠀⠀⠀⇒ h = ut + ½gt²

⠀⠀⠀⠀⇒ h = ½gt²

⠀⠀⠀⠀⇒ 2 = ½ × 10 × t²

⠀⠀⠀⠀⇒ 2 = 5 × t²

⠀⠀⠀⠀⇒ 2/5 = t²

⠀⠀⠀⠀⇒ √(2/5) = t

⠀⠀⠀⠀⇒ <u>0.63 s = t</u>

Therefore, time taken is 0.63 seconds.

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It sounds as though the two people are standing in front of the boat on opposite sides of it, so that they both make an angle of 30.0° with the axis of the boat, as in the attached free body diagram (ignoring the force of buoyancy and the weight of the boat).

By Newton's second law, the net vertical force is

∑ <em>F</em> = <em>P</em>₁ sin(60.0°) + <em>P</em>₂ sin(120.0°) - <em>R</em> = 0

where upward is positive and downward is negative, and the right side is 0 because the boat moves with constant velocity and thus zero acceleration.

We're told that <em>P</em>₁ = <em>P</em>₂ = 600 N, and we know sin(60°) = sin(120°), so the above reduces to

<em>R</em> = 2 <em>P</em> sin(60.0°) = 2 (600 N) sin(60.0°) ≈ 1040 N

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If you sight Polaris with an astrolabe and determine its altitude is 20° above the horizon, then what does this tell you about y
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Three light bulbs are connected to a 9V battery in a series circuit. If
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4 years ago
In a test of an energy-absorbing bumper, a 2800-lb car is driven into a barrier at 5 mi/h. The duration of the impact is 0.4 sec
Fiesta28 [93]

Answer:

F = 2074.13 lb

Explanation:

Given that,

Mass of car, m = 2800 lb = 1270.059 kg

Initial speed, u = 5 mi/h = 2.2352 m/s

Final speed, v = - 1.5 mi/h = -0.67056 m/s  (in opposite direction)

Time, t = 0.4 s

We need to find the magnitude of the average horizontal force (lb) exerted on the car during the impact. It can be calculated as :

F=m\times \dfrac{v-u}{t}\\\\F=1270.059\times \dfrac{-0.67056 -2.2352 }{0.4}\\\\F=9226.21\ N

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