A 2.0 kilogram ball above the floor has 39 joules of potential energy the balls height is about meters above the floor

Physics

2 answers:

Akimi4 [234]3 years ago

8 0

Answer:

the height h is 1.95 m above the floor

Explanation:

m = 2.0 kilogram

Ep = 39 J

g = 10 m/s²

h = ?

Ep = mgh

h = Ep ÷ mg

h = 39 ÷ (2×10)

h = 39÷20

h = 1.95 m

qaws [65]3 years ago

3 0

Answer:

the answer is 2 meters

Explanation:

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You are on the roof of the physics building, 46.0 above the ground . Your physics professor, who is 1.80 tall, is walking alongs

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There is one mistake in the question as unit of height of building is not given.So I assume it as meter.The complete question is here

You are on the roof of the physics building, 46.0 m above the ground. Your physics professor, who is 1.80 m tall, is walking alongside the building at a constant speed of 1.20 m/s. If you wish to drop an egg on your professor’s head, where should the professor be when you release the egg? Assume that the egg is in free fall.

Answer:

d=3.67 m

Explanation:

Height of building=46.0 m

First we need to find time taken by egg to reach 1.80 m above the surface

So to find time use below equation

$S=vt+\frac{1}{2} gt^{2}\\ (46.0-1.80)m=(om/s)t+\frac{1}{2}(9.8m/s^{2} )t^{2}\\t=\sqrt{\frac{(46.0-1.80)m}{4.9} }\\ t=3.06s$