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Novay_Z [31]
3 years ago
5

In a combustion chamber, ethane (C2H6) is burned at a rate of 8 kg/h with air that enters the combustion chamber at a rate of 17

6 kg/h. Determine the percentage of excess air used during this process.
Chemistry
1 answer:
REY [17]3 years ago
4 0

Answer:

37%

Explanation:

From the question, the equation goes does.

C2H6+ (1-x)+a(O2+3.76N2)=bC02 + cH2O + axO2 + 3.76dN2.

Mair=Mair/Rin

( MN)O2 + (MN)N2÷ (MN)O2 + (MN)N2 +(MN)C2H6.

33 . 3.25(1-x) + 28 × 13.16(1-x) ÷ 33 × 3.25(1-x) + 28 × 13.16(1-x). + 30.1

= 176/176+8

X= 0.37

0.37 × 100

X= 37%

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What is the molecular weight, density, and how many moles in
OverLord2011 [107]

Answer:

<em>1) Molecular weight: 18g/mol </em>

<em>Density: at room temperature (25ºC) is 0.997g/mL</em>

<em>Moles: 0.55moles</em>

<em>2) Molecular weight: 182g/mol</em>

<em>Density: at room temperature (25ºC) is 1.11g/mL</em>

<em>Moles: 2.2x10^{-4}moles</em>

Explanation:

1) The molecular formula of water is H_{2}O thus, the molecular weight is the sum of the weights of its atoms.

H: 1g/mol x 2 = 2g/mol

O: 16g/mol x 1 = 16g/mol

H_{2}O: 2g/mol + 16g/mol = 18g/mol

The density (δ) of water at room temperature (25ºC) is 0.997g/mL

Therefore, the weight (m) of 1mL of water is:

m = δ.V = 0.997\frac{g}{mL}. 1mL = 0.997g

Multiplying the mass by its molecular weight gives the number of moles:

\frac{0.997g }{18g/mol} = 0.55 moles

2) The molecular formula of benzophenone is C_{13}H_{10}O thus, the molecular weight is the sum of the weights of its atoms.

C: 12g/mol x 13 = 156g/mol

H: 1g/mol x 10 = 10g/mol

O: 16g/mol x 1 = 16g/mol

C_{13}H_{10}O: 156g/mol + 10g/mol + 16g/mol = 182g/mol

The density (δ) of water at room temperature (25ºC) is 1.11g/mL

Multiplying the mass by its molecular weight gives the number of moles:

\frac{0.04g }{182g/mol} = 2.2x10^{-4}moles

3 0
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Depends on molecule.

Explanation:

The number of the polypeptide chains present in the oligomer depends on the molecule. Some molecules have more polypeptide chains whereas some of them have less polypeptide chains. For example, Hemoglobin is a oligomer that consists of four Polypeptide Chains, two of these Polypeptide Chains are α-globin molecules, each comprise of 141 amino acids, and the other two are (β, γ, δ, or ε) globins, each consist of 146 amino acids.

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