Torch body if I’m wrong I’m really sorry that’s what I got
Answer:
Force per unit plate area is 0.1344 
Solution:
As per the question:
The spacing between each wall and the plate, d = 10 mm = 0.01 m
Absolute viscosity of the liquid, 
Speed, v = 35 mm/s = 0.035 m/s
Now,
Suppose the drag force that exist between each wall and plate is F and F' respectively:
Net Drag Force = F' + F''
where
= shear stress
A = Cross - sectional Area
Therefore,
Net Drag Force, F = 
Also
F = 
where
= dynamic coefficient of viscosity
Pressure, P = 
Therefore,
Answer:
The solution is written in Python
- binary = ""
- decimal = 13
- quotient = int(decimal / 2)
- remainder = decimal % 2
- binary = str(remainder) + binary
-
- while(quotient >0):
- decimal = int(decimal / 2)
- quotient = int(decimal / 2)
- remainder = decimal % 2
- binary = str(remainder) + binary
-
- print(binary)
Explanation:
Firstly, we declare a variable <em>binary</em> and initialize it with an empty string (Line 1). This <em>binary </em>is to hold the binary string.
Next, we declare variable <em>decimal, quotient </em>and<em> remainder </em>(Line 2-4). We assign a test value 13 to decimal variable and then get the first quotient by dividing decimal with 2 (Line 3). Then we get the remainder by using modulus operator, % (Line 4). The first remainder will be the first digit joined with the binary string (Line 5).
We need to repeat the process from Line 3-5 to get the following binary digits. Therefore create a while loop (Line 7) and set a condition that if quotient is bigger than 0 we keep dividing decimal by 2 and calculate the quotient and remainder and use the remainder as a binary digit and join it with binary string from the front (Line 9-11).
At last, we print the binary to terminal (Line 13).
The scalar absolute value (magnitude) of velocity is called speed, being a coherent derived unit whose quantity is measured in the SI (metric system) as metres per second (m/s or m⋅s−1). For example, "5 metres per second" is a scalar, whereas "5 metres per second east" is a vector.
