The solid rod BC has a diameter of 30 mm and is made of an aluminum for which the allowable shearing stress is 25 MPa. Rod AB is
1 answer:
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Answer:
atomic radius R = 0.157 nm
metal atomic weight = 72.27 g/mol
Explanation:
given data
parameters a = 0.413 nm
parameters b = 0.665 nm
parameters c = 0.876 nm
atomic packing factor = 0.536
density = 3.99 g/cm³
to find out
atomic radius and atomic weight
solution
we apply here atomic packing factor (x) that is
atomic packing factor (x) = ..................1
put here value we get
atomic packing factor =
R =
R =
atomic radius R = 0.157 nm
and
now we get here metal atomic weight that is
metal atomic weight = ....................2
metal atomic weight =
metal atomic weight = 72.27 g/mol