Answer: 30.85%.
Step-by-step explanation:
Let X denotes the score of random student.
Given:
and 
We assume that scores are normally distributed.
Then , the probability that a a student score higher than 55:
![P(X>55)=P(\dfrac{X-\mu}{\sigma}>\dfrac{55-50}{10})\\\\=P(Z>0.5) \ \ [Z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E55%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B55-50%7D%7B10%7D%29%5C%5C%5C%5C%3DP%28Z%3E0.5%29%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28Z%3C0.5%29%5C%5C%5C%5C%3D1-0.6915%5C%20%5B%5Ctext%7BBy%20p-value%20table%20for%20z%7D%5D%5C%5C%5C%5C%3D%200.3085)
Hence, the percent of students have a higher score than hers is 30.85%.
Answer:
The Markup was by 25%
Step-by-step explanation:
The answer is 25% because 25% of 64 is 16
25% * 64 = 16
64 + 16 = 80
So, the price markup was by 25%
Hope this helps! :)
Answer:
<em>P</em>arentheses/brackets
<em>E</em>xponents
<em>M</em>ultiply
<em>D</em>ivide
<em>A</em>dd
<em>S</em>ubtract
Divide by 5.
500/5 = 100
100/5 = 20
20/5 = 4