Answer:
A = 92y + 81
Step-by-step explanation:
Because A = number of attendees and if it adds 92 each year, you times the number of years by 92 and add 81 for the ones that were already there
 
        
             
        
        
        
Answer:
0.75 mg
Step-by-step explanation:
From the question given above the following data were obtained:
Original amount (N₀) = 1.5 mg
Half-life (t₁/₂) = 6 years
Time (t) = 6 years
Amount remaining (N) =.? 
Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:
Half-life (t₁/₂) = 6 years
Time (t) = 6 years
Number of half-lives (n) =? 
n = t / t₁/₂
n = 6/6
n = 1
Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:
Original amount (N₀) = 1.5 mg
Half-life (t₁/₂) = 6 years
Number of half-lives (n) = 1
Amount remaining (N) =.?
N = 1/2ⁿ × N₀
N = 1/2¹ × 1.5
N = 1/2 × 1.5
N = 0.5 × 1.5
N = 0.75 mg
Thus, 0.75 mg of the sample is remaining. 
 
        
             
        
        
        
I really gave him a piece of my mind
        
             
        
        
        
Answer:
A) f^-1(x)=(x-8)^3+2
Step-by-step explanation:
To find the function inverse, switch the x with y and solve for y.
![y=\sqrt[3]{x-2}+8 \\\\x=\sqrt[3]{y-2}+8\\\\(x-8)^3 = y-2\\\\ (x-8)^3 + 2 = y](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7Bx-2%7D%2B8%20%5C%5C%5C%5Cx%3D%5Csqrt%5B3%5D%7By-2%7D%2B8%5C%5C%5C%5C%28x-8%29%5E3%20%3D%20y-2%5C%5C%5C%5C%20%28x-8%29%5E3%20%2B%202%20%3D%20y)