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3 years ago

When is an atom least likely to react

Chemistry

2 answers:

Ket [755]3 years ago

6 0

Answer:

The least reactive atoms are those with a filled set of orbitals (octet). The stability of the electrons in atoms determines not only the reactivity of an atom but its valence and the type of chemical bonds it can form.

Hope this helps -_- :)

KonstantinChe [14]3 years ago

4 0

When the atom is stable

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Which statement best describes the variables in a controlled experiment?

RUDIKE [14]

The statement that best describes the variables in a controlled experiment is independent variable while all other conditions are unchanged.

<h3>What is an experiment?</h3>

An experiment is a scientific research, findings or investigation about a subject matter with the aim of validating a claim and establishing theories.

A controlled experiment refers to an experiment in which the variables involved and the control factor are kept in the same group except for one variable which can be changed.

Therefore, The statement that best describes the variables in a controlled experiment is independent variable while all other conditions are unchanged.

Learn more about experiment below.

brainly.com/question/25303029

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3 years ago

PLEASE EXPLAIN what is glucose

antoniya [11.8K]

Answer:

(Hope this helps can I pls have brainlist (crown)☺️)

Explanation:

Glucose is the most common form of sugar in the blood and the body's primary source of energy. Glucose is derived from the meals we eat or produced by the body from other chemicals. The circulation transports glucose to the cells. Several hormones, including insulin, regulate blood glucose levels.

a simple sugar that is a component of many carbohydrates and is a vital source of energy in living things.

Blood sugar, often known as glucose, is the most common sugar present in the body. It is your body's major source of energy and comes from the food you eat. Glucose is carried by your blood to all of your body's cells, where it is used for energy.

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3 years ago

Iron and vanadium both have the BCC crystal structure and V forms a substitutional solid solution in Fe for concentrations up to

Bess [88]

Answer:

Explanation:

To find the concentration; let's first compute the average density and the average atomic weight.

For the average density $\rho_{avg}$ ; we have:

$\rho_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }$

The average atomic weight is:

$A_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }$

So; in terms of vanadium, the Concentration of iron is:

$C_{Fe} = 100 - C_v$

From a unit cell volume $V_c$

$V_c = \dfrac{n A_{avc}}{\rho_{avc} N_A}$

where;

$N_A$ = number of Avogadro constant.

SO; replacing $V_c$ with $a^3$ ; $\rho_{avg}$ with $\dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }$ ; $A_{avg}$ with $\dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }$ and

$C_{Fe}$ with $100-C_v$

Then:

$a^3 = \dfrac { n \Big (\dfrac{100}{[(100-C_v)/A_{Fe} ] + [C_v/A_v]} \Big) } {N_A\Big (\dfrac{100}{[(100-C_v)/\rho_{Fe} ] + [C_v/\rho_v]} \Big) }$

$a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100-C_v)A_{v} ] + [C_v/A_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100-C_v)/\rho_{v} ] + [C_v \rho_{Fe}]} \Big) }$

$a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100A_{v}-C_vA_{v}) ] + [C_vA_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100\rho_{v} - C_v \rho_{v}) ] + [C_v \rho_{Fe}]} \Big) }$

Replacing the values; we have:

$(0.289 \times 10^{-7} \ cm)^3 = \dfrac{2 \ atoms/unit \ cell}{6.023 \times 10^{23}} \dfrac{ \dfrac{100 (50.94 \g/mol) (55.84(g/mol)} { 100(50.94 \ g/mol) - C_v(50.94 \ g/mol) + C_v (55.84 \ g/mol) } }{ \dfrac{100 (7.84 \ g/cm^3) (6.0 \ g/cm^3 } { 100(6.0 \ g/cm^3) - C_v(6.0 \ g/cm^3) + C_v (7.84 \ g/cm^3) } }$

$2.41 \times 10^{-23} = \dfrac{2}{6.023 \times 10^{23} } \dfrac{ \dfrac{100 *50*55.84}{100*50.94 -50.94 C_v +55.84 C_v} }{\dfrac{100 * 7.84 *6}{600-6C_v +7.84 C_v} }$

$2.41 \times 10^{-23} (\dfrac{4704}{600+1.84 C_v})=3.2 \times 10^{-24} ( \dfrac{284448.96}{5094 +4.9 C_v})$

$\mathbf{C_v = 9.1 \ wt\%}$

4 0

3 years ago

Which ion has the same electron configuration as an atom of He?

mariarad [96]

Answer;

H- (negatively charged hydrogen ion)

Explanation;

The hydrogen ion has the same electron configuration as an atom of Helium. -Hydrogen ion is formed when a hydrogen atom loses or gains an electron. A positively charged ion is formed when hydrogen atom loses an electron (remaining with zero electrons) while a negatively charged ion (H-) is formed when a hydrogen atom gains an electron thus having 2 electrons.

-Helium atom has two electrons, therefore, it is similar with an negatively charged hydrogen.

3 0

3 years ago

Read 2 more answers

Find the heat produced from an 8.00 L cylinder of propane gas under 5.00 atm at 25.0 oC, if one mole of propane can produce 2220

Andrei [34K]

Answer: 3597 kJ of heat

Explanation:

According to ideal gas equation:

$PV=nRT$