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Vedmedyk [2.9K]
3 years ago
13

Me :) do you like me i do not like my half sister abby i do know that i probaly look ugly

Health
1 answer:
BartSMP [9]3 years ago
6 0

Answer: Hi! You are very pretty! And don’t let anyone tell you otherwise! :)

Explanation:

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Lina20 [59]

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A specialist in the field of study of the aging: geriatric_____
nata0808 [166]
Geriatrician's are specialist in the field of study of the aging also known as <span>gerontology.</span>
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3 years ago
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Speed training increases one's maximum velocity. Please select the best answer from the choices provided. T F
Furkat [3]

the answer would be true.

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3 years ago
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Differentiate the following functions (i) x(1+x)^3​
statuscvo [17]

Answer:

\displaystyle y' = (1 + x)^2(4x + 1)

General Formulas and Concepts:

<u>Algebra I</u>

  • Terms/Coefficients
  • Functions
  • Function Notation
  • Factoring

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative Property [Addition/Subtraction]:                                                                \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                                \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Derivative Rule [Chain Rule]:                                                                                       \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Explanation:

<u>Step 1: Define</u>

<em>Identify</em>

y = x(1 + x)³

<u>Step 2: Differentiate</u>

  1. Product Rule [Derivative Rule - Chain Rule]:                                                  \displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot \frac{d}{dx}[1 + x]
  2. Derivative Property [Addition/Subtraction]:                                                    \displaystyle y' = \frac{d}{dx}[x] \cdot (1 + x)^3 + x \cdot \frac{d}{dx}[(1 + x)^3] \cdot (\frac{d}{dx}[1] + \frac{d}{dx}[x])
  3. Basic Power Rule:                                                                                             \displaystyle y' = x^{1 - 1} \cdot (1 + x)^3 + x \cdot 3(1 + x)^{3 - 1} \cdot (0 + x^{1 - 1})
  4. Simplify:                                                                                                             \displaystyle y' = (1 + x)^3 + 3x(1 + x)^2
  5. Factor:                                                                                                               \displaystyle y' = (1 + x)^2 \bigg[ (1 + x) + 3x \bigg]
  6. Combine like terms:                                                                                         \displaystyle y' = (1 + x)^2(4x + 1)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0
3 years ago
Arrow Corporation makes archery supplies. While using an Arrow bow, Balto is injured due to a defect in the bow that causes an a
asambeis [7]

Answer:

c. Balto and chu

Explanation: This is because both of them were injured during the course of using the arrow.

Product liability suit occurs in cases of injuries related by a defective product. When manufacturers fail to exercise due care then they are liable to any person who sustained injury, he or she would be held for negligence. Also those who make, sell, or lease goods can be held liable for physical harm or property damage caused by those goods to a consumer.Thia is why a manufacturer's duty of care should extend to the inspection and testing of the final product.

5 0
3 years ago
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