Complex analysis/Compute:<br><br> 2+i/2-i=

what is the point-slope form of the equation of the line passing through the points (–6, –4) and (2, –5).

ioda

Answer:

The equation of the line would be y + 4 = -1/8(x + 6)

Step-by-step explanation:

To find the point-slope form of the line, start by finding the slope. You can do this using the slope formula below along with the two points.

m(slope) = (y2 - y1)/(x2 - x1)

m = (-4 - -5)/(-6 - 2)

m = 1/-8

m = -1/8

Now that we have the slope, we can use that along with one of the points in the base form of point-slope.

y - y1 = m(x - x1)

y + 4 = -1/8(x + 6)

7 0

3 years ago

ANSWER FAST PLEASE <br> what is the degree of the polynomial

STatiana [176]

Answer:

The degree of a polynomial is the largest exponent on one of its variables (for a single variable), or the largest sum of exponents on variables in a single term (for multiple variables).

Step-by-step explanation:

ere, the term with the largest exponent is , so the degree of the whole polynomial is 6.

3 0

2 years ago

HELP PLEASE

Anna [14]

For a cone, the equation for volume would be
V = π r^2 h/3.

( volume = pi x radius squared x height / 3)

To find the volume for this question, you would set up the equation like this:

V = π x 2^2 x 12 / 3

Then, following the order of operation, you would do the following:

V = π x 4 x 12 / 3

(You get the 4 from 2 squared)

V = π x 4 x 4

(You get the second 4 from dividing 12 by 3)

V = π x 16

(You get 16 from multiplying 4 and 4)

V = 16π

(You get 16π from multiplying 16 and π, and the number is always in front of the π, so you would never get a π16, it would only be 16π)

So, your volume would be 16π, which is answer D.

I hope I helped! c:

7 0

2 years ago

Find the extremum of f(x,y) subject to the given constraint, and state whether it is a maximum or a minimum. f(x,y)=4x2 2y2; 3x

nevsk [136]

For given f(x, y) the extremum: (12, 24) which is the minimum.

For given question,

We have been given a function f(x) = 4x² + 2y² under the constraint 3x+3y= 108

We use the constraint to build the constraint function,

g(x, y) = 3x + 3y

We then take all the partial derivatives which will be needed for the Lagrange multiplier equations:

$f_x=8x$

$f_y=4y$

$g_x=3$

$g_y=3$

Setting up the Lagrange multiplier equations:

$f_x=\lambda g_x$

⇒ 8x = 3λ .....................(1)

$f_y=\lambda g_y$

⇒ 4y = 3λ ......................(2)

constraint: 3x + 3y = 108 .......................(3)

Taking (1) / (2), (assuming λ ≠ 0)

⇒ 8x/4y = 1

⇒ 2x = y

Substitute this value of y in equation (3),

⇒ 3x + 3y = 108

⇒ 3x + 3(2x) = 108

⇒ 3x + 6x = 108

⇒ 9x = 108

⇒ x = 12

⇒ y = 2 × 12

⇒ y = 24

So, the saddle point (critical point) is (12, 24)

Now we find the value of f(12, 24)

⇒ f(12, 24) = 4(12)² + 2(24)²

⇒ f(12, 24) = 576 + 1152

⇒ f(12, 24) = 1728 ................(1)

Consider point (18,18)

At this point the value of function f(x, y) is,

⇒ f(18, 18) = 4(18)² + 2(18)²

⇒ f(18, 18) = 1296 + 648

⇒ f(18, 18) = 1944 ..............(2)

From (1) and (2),

1728 < 1944

This means, given extremum (12, 24) is minimum.

Therefore, for given f(x, y) the extremum: (12, 24) which is the minimum.

Learn more about the extremum here:

brainly.com/question/17227640

#SPJ4

6 0

1 year ago

Can you find the area

jonny [76]

Answer:

45in.

Step-by-step explanation:

3 0

3 years ago

Complex analysis/Compute: 2+i/2-i=