Answer:
Mean = 3640
Mode = 4100
Median = 3830.
Step-by-step explanation:
We are given the following data in the question:
Strength of casts (in psi):
3970,4100,3100,3200,2950,3830,4100,4050,3460
Formula:
![Mean = \displaystyle\frac{\text{Sum of all observation}}{\text{Total number of observations}}](https://tex.z-dn.net/?f=Mean%20%3D%20%5Cdisplaystyle%5Cfrac%7B%5Ctext%7BSum%20of%20all%20observation%7D%7D%7B%5Ctext%7BTotal%20number%20of%20observations%7D%7D)
![\displaystyle\frac{3970+4100+3100+ 3200+ 2950+ 3830+4100+ 4050+ 3460}{9} = \displaystyle\frac{32760} {9} = 3640](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B3970%2B4100%2B3100%2B%203200%2B%202950%2B%203830%2B4100%2B%204050%2B%203460%7D%7B9%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7B32760%7D%20%7B9%7D%20%3D%203640)
Mode is the entry with most frequency. Thus, for the given sample mode = 4100.
Median
Since n = 9 is odd,
Formula:
![Median = \displaystyle\frac{n+1}{2}th~term](https://tex.z-dn.net/?f=Median%20%3D%20%5Cdisplaystyle%5Cfrac%7Bn%2B1%7D%7B2%7Dth~term)
Data in ascending order:
2950,3100,3200,3460,3830,3970,4050,4100,4100
Median = 5th term = 3830.