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FinnZ [79.3K]
3 years ago
5

Help please :)))))))))))))))))))))))))))))))

Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0

Answer:

(-4-5)0=1 because parentheses is raised to the zero power

or this becomes (-4[-5*0])=(-40)=1

or,...

(1/-45)0=(1/-1024)0=(-1/1024)0=1Step-by-step explanation:

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1/4 long divison work
Ilia_Sergeevich [38]

Answer:

0.25

Step-by-step explanation:

8 0
3 years ago
Need help.................................
OlgaM077 [116]
The answer should be A





Hope this helps :)
7 0
3 years ago
Read 2 more answers
5. The measure of an intercepted arc is 86, and the measure of the inscribed angle creating the intercepted arc is 3x +
Nonamiya [84]

Answer:

Th correct option is D. 13

Therefore the value of x is 13.

Step-by-step explanation:

Given:

measure of an intercepted arc = 86°

Center Angle = 86°

measure of the inscribed angle creating the intercepted arc= (3x+4)°

Angle Inscribed in arc = (3x+4)°

To Find:

value of x = ?

Solution:

Inscribed Angle Theorem:

The inscribed angle theorem states that an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle.

\textrm{Angle Inscribed in arc}=\dfrac{1}{2}\textrm{Center Angle}

Substituting the values we get

3x+4=\dfrac{1}{2}86=43\\\\3x=39\\\\x=\dfrac{39}{3}=13\\\\x=13

Therefore the value of x is 13.

4 0
3 years ago
A store sells candy at $.50, $1, $1.50, $2, and $3 per kilogram. you can see that the unit price of candies that $3 buy very inv
olga nikolaevna [1]

Answer:

constant of variation = 3

Step-by-step explanation:

Given that a store is selling different candies costing  $.50, $1, $1.50, $2, and $3 per kilogram.

As given

Amount available to buy candies = $ 3

Suppose

Unit price of candies = x

Number of candies bough = y

Constant of variation = k

As we know the unit price of candies and number of candies bought vary inversely. As the unit price would increase the the number of candies bought in available amount ($3) would decrease.

So our formula to calculate formula for constant of variation would be as shown below:

k= xy →(1

Case 1

if we take unit price x to be $0.5, then we can buy 6 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (0.5)(6) = 3

Case 2

if we take unit price x to be $1, then we can buy 3 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1)(3) = 3

Case 3

if we take unit price x to be $1.5, then we can buy 2 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (1.5)(2) = 3

Case 4

if we take unit price x to be $2, then we can buy 1.5 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (2)(1.5) = 3

Case 4

if we take unit price x to be $3, then we can buy 1 kg of candies in $ 3. In this case constant of variation can be found from above equation (1) as follows:

k = (3)(1) = 3

So, our constant of variation is 3.

3 0
3 years ago
A geologist have two rocks on a scale that weighs 2 1/2 lbs together rock a was 1/7 of a the total weight how much did rock a we
katen-ka-za [31]
Simply get the product of 2 and 1/2 by 1/7.

firstly, let's convert the mixed fraction to "improper" and then multiply.

\bf \stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}}\qquad \qquad \cfrac{5}{2}\cdot \cfrac{1}{7}\implies \stackrel{\textit{rock A weight}}{\cfrac{5}{14}}
4 0
4 years ago
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