Answer:
She can travel 24 miles in 3 hours.
Answer:
Push and pull both are forces , but the difference is in their direction at which it is applied . If the force applied in the direction of motion of the particle then we call it as push . If that force applied in the direction OPPOSITE to the motion of particle then it is termed as pull
Answer:
i dont know but what i could say is you could go on and ask the question and it would help you
Explanation:
Answer:
![t - t_1 = \frac{-\omega_o + \sqrt{\omega_o^2 + 8\alpha(2\omega_o t + \alpha t^2)}}{4\alpha}](https://tex.z-dn.net/?f=t%20-%20t_1%20%3D%20%5Cfrac%7B-%5Comega_o%20%2B%20%5Csqrt%7B%5Comega_o%5E2%20%2B%208%5Calpha%282%5Comega_o%20t%20%2B%20%5Calpha%20t%5E2%29%7D%7D%7B4%5Calpha%7D)
Explanation:
After time "t" the angular position of A is given as
![\theta_a = \theta_o + \omega_o t + \frac{1}{2}\alpha t^2](https://tex.z-dn.net/?f=%5Ctheta_a%20%3D%20%5Ctheta_o%20%2B%20%5Comega_o%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%5Calpha%20t%5E2)
now we know that B start motion after time t1
so its angular position is also same as that of position of A after same time "t"
so we have
![\theta_b = \theta_o + \frac{\omega_o}{2} (t - t_1) + \frac{1}{2}(2\alpha) (t - t_1)^2](https://tex.z-dn.net/?f=%5Ctheta_b%20%3D%20%5Ctheta_o%20%2B%20%5Cfrac%7B%5Comega_o%7D%7B2%7D%20%28t%20-%20t_1%29%20%2B%20%5Cfrac%7B1%7D%7B2%7D%282%5Calpha%29%20%28t%20-%20t_1%29%5E2)
now since both positions are same
![\theta_a = \theta_b](https://tex.z-dn.net/?f=%5Ctheta_a%20%3D%20%5Ctheta_b)
![\omega_o t + \frac{1}{2}\alpha t^2 = \frac{\omega_o}{2}(t - t_1} + \alpha(t - t_1)^2](https://tex.z-dn.net/?f=%5Comega_o%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%5Calpha%20t%5E2%20%3D%20%5Cfrac%7B%5Comega_o%7D%7B2%7D%28t%20-%20t_1%7D%20%2B%20%5Calpha%28t%20-%20t_1%29%5E2)
![2\omega_o t + \alpha t^2 = \omega_o(t - t_1) + 2\alpha(t - t_1)^2](https://tex.z-dn.net/?f=2%5Comega_o%20t%20%2B%20%5Calpha%20t%5E2%20%3D%20%5Comega_o%28t%20-%20t_1%29%20%2B%202%5Calpha%28t%20-%20t_1%29%5E2)
![t - t_1 = \frac{-\omega_o + \sqrt{\omega_o^2 + 8\alpha(2\omega_o t + \alpha t^2)}}{4\alpha}](https://tex.z-dn.net/?f=t%20-%20t_1%20%3D%20%5Cfrac%7B-%5Comega_o%20%2B%20%5Csqrt%7B%5Comega_o%5E2%20%2B%208%5Calpha%282%5Comega_o%20t%20%2B%20%5Calpha%20t%5E2%29%7D%7D%7B4%5Calpha%7D)