Answer:
the buoyant force acting on the ice cube is 0.119 N
Explanation:
given,
volume of ice cube = 15 cm³ = 15 × 10⁻⁶ m³
density of ice cube = 917 kg/m³
density of ethyl alcohol = 811 kg/m³
buoyant force = ?
The density of ice is more than ethyl alcohol hence it will sink.
buoyant force acting on the ice cube = ρ V g
= 811 × 15 × 10⁻⁶ × 9.81
=0.119 N
so, the buoyant force acting on the ice cube is 0.119 N
Answer:
Explanation:
Given:
Initial velocity, u = 0 m/s (at rest)
Final velocity, v = 22 m/s
Time, t = 9 s
Diameter, d = 58 cm
Radius, r = 0.29 m
Using equation of motion,
v = u + at
a = (22 - 0)/9
= 2.44 m/s^2
v^2 = u^2 + 2a × S
S = (22^2 - 0^2)/2 × 2.44
= 99.02 m
S = r × theta
Theta = 99.02/0.29
= 341.44 °
1 rev = 360°
341.44°,
= 341.44/360
= 0.948 rev
= 0.95 rev
B.
Final angular speed, wf = v/r
= 22/0.29
= 75.86 rad/s
Answer:
3420.39 N
Explanation:
Applying,
Fd = 1/2(mv²-mu²)................. Equation 1
Where F = force on the bumber, d = distance, m = mass of the car, v = final velocity, u = initial velocity.
make F the subject of the equation
F = (mv²-mu²)/2d............... Equation 2
From the question,
Given: m = 890 kg, v = 0 m/s (to rest), u = 1.4 m/s, d = 0.255 m
Substitute these values into equation 2
F = [(890×0²)-(890×1.4²)]/(2×0.255)
F = -1744.4/0.51
F = -3420.39 N
The negative sign denotes that the force in opposite direction to the motion of the car.
Answer: A balloon provides a simple example of how a rocket engine works. The air trapped inside the balloon pushes out the open end, causing the balloon to move forward. The force of the air escaping is the "action"; the movement of the balloon forward is the "reaction" predicted by Newton's Third Law of Motion.
Explanation: ur welcome
Answer:
nothing travels faster than light
Example:
You’ll always see lightning before you hear it, because typically lightning will be a mile away, two miles away.
