She does 200J .
We know she uses 20N of force and 10m is the distance. We multiply both numbers and we are given our answer of 200J. Hope this was helpful. :)
Answer:
(a) B = 2.85 ×
Tesla
(b) I = I = 0.285 A
Explanation:
a. The strength of magnetic field, B, in a solenoid is determined by;
r = ![\frac{mv}{qB}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%7D%7BqB%7D)
⇒ B = ![\frac{mv}{qr}](https://tex.z-dn.net/?f=%5Cfrac%7Bmv%7D%7Bqr%7D)
Where: r is the radius, m is the mass of the electron, v is its velocity, q is the charge on the electron and B is the magnetic field
B = ![\frac{9.11*10^{-31*1.0*10^{4} } }{1.6*10^{-19}*0.02 }](https://tex.z-dn.net/?f=%5Cfrac%7B9.11%2A10%5E%7B-31%2A1.0%2A10%5E%7B4%7D%20%7D%20%7D%7B1.6%2A10%5E%7B-19%7D%2A0.02%20%7D)
= ![\frac{9.11*10^{-27} }{3.2*10^{-21} }](https://tex.z-dn.net/?f=%5Cfrac%7B9.11%2A10%5E%7B-27%7D%20%7D%7B3.2%2A10%5E%7B-21%7D%20%7D)
B = 2.85 ×
Tesla
b. Given that; N/L = 25 turns per centimetre, then the current, I, can be determined by;
B = μ I N/L
⇒ I = B ÷ μN/L
where B is the magnetic field, μ is the permeability of free space = 4.0 ×
Tm/A, N/L is the number of turns per length.
I = B ÷ μN/L
= ![\frac{2.85*10^{-6} }{4*10^{-7} *25}](https://tex.z-dn.net/?f=%5Cfrac%7B2.85%2A10%5E%7B-6%7D%20%7D%7B4%2A10%5E%7B-7%7D%20%2A25%7D)
I = 0.285 A
Answer:
The normal force will be "122.8 N".
Explanation:
The given values are:
Weight,
W = 100 N
Force,
F = 40 N
Angle,
θ = 35.0°
As we know,
⇒ ![N=W+FSin \theta](https://tex.z-dn.net/?f=N%3DW%2BFSin%20%5Ctheta)
On substituting the given values, we get
⇒ ![= 100N+40N \ Sin \theta](https://tex.z-dn.net/?f=%3D%20100N%2B40N%20%5C%20Sin%20%5Ctheta)
⇒ ![=100N+22.8](https://tex.z-dn.net/?f=%3D100N%2B22.8)
⇒ ![=122.8 \ N](https://tex.z-dn.net/?f=%3D122.8%20%5C%20N)
Answer:
A downward force of magnitude 5 N is exerted on the book by the force of ... Do the downward force in Part A (gravity) and the upward force in Part B ...