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umka2103 [35]
2 years ago
8

When an object moves in a circle the

Physics
1 answer:
V125BC [204]2 years ago
5 0

Answer:

constantly changing its direction

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A laser beam of unknown wavelength passes through adiffraction grating having 5510 lines/cm after striking itperpendicularly. Ta
Ivahew [28]

Answer:

Explanation:

distance between two slit  d = \frac{1 \times 10^{-2}}{5510}

d = 18.15 x 10⁻⁷ m

Let wave length of light λ

formula for  position of  first pair of bright spot

Tanθ = λ / d , λ is wave length of light and d is distance between two slit .

Tan 15.4 = \frac{\lambda}{18.15\times10^{-7}}

λ = Tan 15.4 x 18.15 x 10⁻⁷

=5 x 10⁻⁷ m

If θ be the position of next bright spot

Tanθ = 2 λ / d

= \frac{2 \times\ 5\times\ 10^ {-7}}{18.15\times10^{-7}}

=\frac{2\times5}{18.5}

θ = 28.4 degree .

7 0
4 years ago
A force of 6 N is used to open a door, wherein the distance of the force to the axis of rotation is 80 cm. If the angular accele
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Explanation:

∑τ = Iα

(6 N) (0.80 m) = I (0.5 rad/s²)

I = 9.6 kg m²

7 0
4 years ago
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A real power supply can be modeled as an ideal EMF of 60 Volts in series with an internal resistance. The voltage across the ter
lara31 [8.8K]

Answer:

5 ohms

Explanation:

Given:

EMF of the ideal battery (E) = 60 V

Voltage across the terminals of the battery (V) = 40 V

Current across the terminals (I) = 4 A

Let the internal resistance be 'r'.

Now, we know that, the voltage drop in the battery is given as:

V_d=Ir

Therefore, the voltage across the terminals of the battery is given as:

V= E-V_d\\\\V=E-Ir

Now, rewriting in terms of 'r', we get:

Ir=E-V\\\\r=\frac{E-V}{I}

Plug in the given values and solve for 'r'. This gives,

r=\frac{60-40}{4}\\\\r=\frac{20}{4}\\\\r=5\ ohms

Therefore, the internal resistance of the battery is 5 ohms.

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4 years ago
Which type of boundary is modeled?
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A is convergent
B is
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