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Radda [10]
3 years ago
10

Why x ray is called an electromagnetic wave​

Physics
1 answer:
Dahasolnce [82]3 years ago
7 0
Because they behave just like all the electromagnetic waves of the spectrum. Same equations, just shorter wavelengths and more energy.

Hope you get it :)
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When a baseball is thrown straight upward, what is its acceleration at its greatest height?
Troyanec [42]
I believe the correct answer from the choices listed above is option C. When a baseball is thrown straight upward, <span>its acceleration at its greatest height would be 0 m/s. This is because at max height velocity of the ball is zero which means that acceleration as well is zero. Hope this answers the question. Have a nice day.</span>
5 0
3 years ago
Read 2 more answers
A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.6 multiply 1010 m (inside t
Doss [256]

We will apply the concepts related to energy conservation to develop this problem. In this way we will consider the distances and the given speed to calculate the final speed on the path from the sun. Assuming that the values exposed when saying 'multiply' is scientific notation we have the following,

d_1 = 4.6*10^{10}m

v_i = 9.3*10^4m/s \rightarrow \text{Initial velocity comet}

d_2 = 6*10^{12}m

The difference of the initial and final energy will be equivalent to the work done in the system, therefore

E_f = E_i +W

K_f +U_f = K_i +U_i + 0

\frac{1}{2} mv_f^2+\frac{-GMm}{d_2} = \frac{1}{2} mv_i^2+\frac{-GMm}{d_1}

Here,

m = Mass

v_f = Final velocity

G = Gravitational Universal Constant

M = Mass of the Sun

m = Mass of the comet

v_i = Initial Velocity

Rearranging to find the final velocity,

v_f = \sqrt{v_i^2+2GM(\frac{1}{d_2}-\frac{1}{d_1})}

Replacing with our values we have finally,

v_f = \sqrt{(9.3*10^4)+2(6.7*10^{-11})(1.98*10^{30})(\frac{1}{6*10^{12}}-\frac{1}{4.6*10^{10}})}

v_f = 75653.9m/s

Therefore the speed is 75653m/s

8 0
4 years ago
What are the dimensions of potential energy?​
Pachacha [2.7K]

Potential Energy (P.E) = Mass x

Acceleration due to Gravity x Altitude. Putting this value in the above equation we get, Dimensional Formula of

Potential energy= M1L2T-2.

5 0
3 years ago
develop an equation with a proportionality constant that describes the relationship between the gravitational force the mass of
Ganezh [65]
Let the mass of planet and moon be Mp and Mn respectively.
And the distance between them is "r"

Then according to Newton's law of gravitation,

The force with which the planet and the moon attract esch other is
1) directly proportional to the product of their masses i.e. Mp * Mn

2) inversly proportional to the square of the distance between them i.e r ^2

Therefore,F =. G (Mp* Mn)/r^2
Where,G is gravitational constant
3 0
4 years ago
If he completes the 200 m dash in 23 s and runs at constant speed throughout the race, what is his centripetal acceleration as h
Blababa [14]

Incomplete question.The complete one is here

A runner taking part in the 200m dash must run around the end of a track that has a circular arc with a radius curvature of 30m. The runner starts the race at a constant speed. If she completes the 200m dash in 23s and runs at constant speed throughout the race, what is her centripetal acceleration as she runs the curved portion of the track?

Answer:

a_c=2.523m/s^2

Explanation:

Given data

L_{length}=200m\\r_{radius}=30m\\t_{time}=23s

Required

Centripetal acceleration

Solution

According to the motions equation the velocity given by:

V_{velocity}=\frac{L_{length}}{t_{time}}\\V_{velocity}=\frac{200m}{23s}\\V_{velocity}=8.7m/s

The centripetal acceleration is given by:

a_{c}=\frac{V_{velocity}^2}{r_{radius}}\\ a_c=\frac{(8.7m/s)^2}{30m}\\ a_c=2.523m/s^2

4 0
4 years ago
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